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gizmo_the_mogwai [7]
3 years ago
13

which of the following structures are tubes? A. Eustachian, Pharynx, Bronchi. B. Cilia, Adenoids, mucous, epiglottis. C. Apex, M

Axillary, sphenoidal, ethmoidal?
Chemistry
1 answer:
Arte-miy333 [17]3 years ago
6 0
The correct answer among the choices given is option A. Eustachian, Pharynx, Bronchi are structures that ensembles a tube. The Eustachian tube is a narrow passage from the pharynx to the middle ear. Pharynx is a passageway leading from the oral and nasal cavities to the larynx and the esophagus. Lastly, bronchi is an airway in the respiratory tract.
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Suppose you start with a solution of red dye #40 that is 2.3 ✕ 10−5 M. If you do three successive volumetric dilutions pipetting
larisa [96]

Answer: Therefore, the concentration of final solution is 4.0\times 10^{-8}M

Explanation:

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 2.3\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

2.3\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=0.28\times 10^{-5}M

Therefore, the concentration of diluted solution is 0.28\times 10^{-5}M

2) On further dilution

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.28\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

0.28\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=0.034\times 10^{-5}M

Therefore, the concentration of diluted solution is 0.034\times 10^{-5}M

3) On further dilution

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.034\times 10^{-5}M

V_1 = volume of stock solution = 3.00 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 25.00 ml

0.034\times 10^{-5}M\times 3.00=M_2\times 25.00

M_2=4.0\times 10^{-8}M

Therefore, the concentration of final solution is 4.0\times 10^{-8}M

5 0
3 years ago
Calculate the number of molecules in 2.5 moles of sucrose.
iris [78.8K]
1.51 x 10^24 molecules
3 0
3 years ago
What is the Na+ concentration in each of the following solutions:
KIM [24]
<h3>a) <u>Answer;</u></h3>

A- 7.30 M

<h3><u>Explanation;</u></h3>

3.65 Sodium sulfate

Na2(SO4) dissociates to give sodium ions and sulfate ions.

Na2(SO4) → 2Na+ + SO₄²₋

Therefore, twice the concentration of sodium ions as far as molarity is concerned.

<em><u>Concentration of sodium ions = 3.65 × 2= 7.3 M</u></em>

<h3>b) <u> Answer;</u></h3>

B- 2.76 M

<h3><u>Explanation;</u></h3>

b) 1.38 M sodium carbonate

Sodium carbonate dissociates completely to yield Sodium ions and carbonate ions

Na₂CO₃ → 2Na+ + CO₃²₋

The concentration of sodium ions will be twice the concentration of initial compound since it has a ratio of two.

<em>Concentration of sodium ions = 1.38 ×2 </em>

<em>                                                   = 2.76 M</em>

<h3>c) <u>Answer;</u></h3>

<em>0.785 M</em>

<h3><u>Explanation;</u></h3>

b) 0.785 sodium bicarbonate

Sodium bicarbonate dissociates completely to sodium ions and a bicarbonate ions.

NaHCO₃ →Na+ + HCO₃⁻

In this case the concentration of Na+ will be equal to the concentration of the original compound since they share the same ratio.

Thus; <em><u>Na+ concentration = 0.785 M</u></em>

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3 years ago
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They would most likely get sick. Or suffer from organ failure. When one part of your body doesn’t work it causes a weakness, making you more susceptible to sicknesses.
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3 years ago
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Convert 8.4 • 10^16 molecules of CO2 to moles
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Answer:

0.00000000000000084

Explanation:

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