Where are the images?!?!?
Answer:
Power output: W=1426.9MW
Explanation:
The power output of the falls is given mainly by its change in potential energy:
![Q=-P_{tot}=-(P_{2}-P_{1})](https://tex.z-dn.net/?f=Q%3D-P_%7Btot%7D%3D-%28P_%7B2%7D-P_%7B1%7D%29)
The potential energy for any point can be calculated as:
![P=m*g*h](https://tex.z-dn.net/?f=P%3Dm%2Ag%2Ah)
If we consider the base of the falls to be the reference height, at point 2 h=0, so P2=0, and height at point 1 equals 52m:
![Q=P_{1}=m*g*h](https://tex.z-dn.net/?f=Q%3DP_%7B1%7D%3Dm%2Ag%2Ah)
If we replace m with the mass rate M we obtain the rate of change in potential energy over time, so the power generated:
![W=M*g*h=2.8*10^{3}m^{3}/s*1*10^{3}kg/m^{3}*9.8m/s^{2}*52m =1426.9MW](https://tex.z-dn.net/?f=W%3DM%2Ag%2Ah%3D2.8%2A10%5E%7B3%7Dm%5E%7B3%7D%2Fs%2A1%2A10%5E%7B3%7Dkg%2Fm%5E%7B3%7D%2A9.8m%2Fs%5E%7B2%7D%2A52m%20%3D1426.9MW)
Question: What was his initial velocity?
Answer: 3.62 m/s
Answer:
(C) Average Velocity = 25 m/s due North