The answer is D so mars hope i helped
:)
Answer:
The normal force applied by block on the ground is (mg - F cosФ)
Explanation:
<em>Lets explain how to solve the problem</em>
At first you must distribute the force F into two components
<em>Vertical</em> component which is <em>F cosФ</em>
<em>Horizontal</em> component which is <em>F sinФ</em>
The block is in equilibrium, that means sum of forces acting on the
block is zero
So the upward forces equal the downward forces
Normal reaction force R applied by block on the ground and the
vertical component of F both are upward forces
The weight of the block is downward force
The normal reaction force R plus the vertical component of F is
equal to the weight
<em>R + F cosФ = W</em>
W = mg, where g is acceleration of gravity and m is the mass of
the block
<em>R + F cosФ = mg</em>
Subtract F cosФ from both sides
<em>R = mg - F cosФ</em>
<em></em>
The normal force applied by block on the ground is (mg - F cosФ)
Hence the velocity is 16.3 m/s
Answer:
Final velocity will be equal to 0.321 m/sec
Explanation:
We have given mass of clay model of lion 
Its speed is 0.85 m/sec, so 
Mass of another clay model 
It is given that second clay is motionless
So its velocity 
Now according to conservation of momentum
Momentum before collision will be equal to momentum after collision
So 
, here v is velocity after collision
So 
v = 0.321 m/sec
So final velocity will be equal to 0.321 m/sec
Answer:
Mathematical
Explanation:
Because you are comparing the length and width
