Answer:
4.4 m/s
Explanation:
momentum is always conserved so we can use conversation of momentum to solve the question, also momentum is a vector quantity ( it has magnitude and direction) which is the product of the bodies mass and velocity.
conservation law of momentum relates by the formula below:
momentum before collision = momentum after collision
M1U1 + M2U2 = M1V1 + M2V2
in the case of this two, the formula becomes
M1U1 + M2U2 = V (M1 + M2) since she jumped into his arm
there masses are M1 = 75.6 kg M2 = 59 kg and their velocities are U1 = 3.7 m/s and U2 = 5.4 m/s, their common velocity after collision = V since their motion is backward the formula becomes
-M1U1 - M2U2 = V(M1 + M2)
substitute the values into the equations
(-75.6 × 3.7 ) + (- 59 × 5.4) = V ( 75.6 + 59)
- 598.32 = 134.6 V
divide both side by 134.6
V = - 598.32 / 134.6 = -4.445 m/s = -4.4 m/s to nearest tenth the negative means in the same backward direction
