Answer:
all th eabove i had this pls give brainliest i got this correct of of edmentum
Explanation:
Answer:
The law of conservation of mass states that mass cannot be created or destroyed only transfered. So when a size change takes place the mass is being transfered into something else. During a state change the mass is being transfered into another state of matter. When a substance dissolves into another liquid the mass is still their just into another state.
Explanation:
Answer:
One element takes the place of another in a compound
Explanation:
I just took a test for it and got it right. :)
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10 electrons in an atom can have each of the 3d quantum number or sublevel designations.
<h3>What are four quantum numbers?</h3>
Quantum numbers are used to characterize the values of conserved quantities in a quantum system's dynamics in both quantum physics and chemistry.
1) The "n" sign refers to the principal quantum number. It shows how many shells there are.
2) The "l" sign indicates the azimuthal quantum number. It gives the form of the orbitals and their angular momentum. 0 to n-1 make up its range.
3) "
" stands for the magnetic quantum number. It serves as a cue for spatial orientation. The range of it is -l to +l.
4) Spin quantum number, represented by the symbol "
". It shows how the electron is spinning.
Learn more about quantum numbers here:
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I have attached an image that shows the reaction and each isomer formed.
The oxygen of the epoxide adds syn to the alkene, which means the oxygen is on one face of the molecule. Therefore, the epoxide has 2 chiral centers. The dimethyl amine is a nucleophile and it attack a carbon bound to oxygen in an sn2 fashion. This causes the epoxide ring to open, and after a proton transfer, the molecule now has a dimethyl amino group and an adjacent hydroxy group in an anti-relationship. The amine is able to attack either of the two carbons bound to the oxygen in the epoxide and this leads to two isomers. The isomers formed are a pair of enantiomers with the stereochemistry (<em>R,R</em>) and (<em>S,S</em>). Therefore, the second isomer that the question asks for is the (<em>S,S</em>) product shown.