The mass would be same because of the law of conservation which states that the mass of the reactants must equal to the mass of products
        
             
        
        
        
Answer:
The answer to your question is 25.2 g of acetic acid.
Explanation:
Data
[Acetic acid] = 0.839 M
Volume = 0.5 L
Molecular weight = 60.05 g/mol
Process
1.- Calculate the number of moles of acetic acid 
     Molarity = moles / volume
-Solve for moles
     moles = Molarity x volume
-Substitution
     moles = (0.839)(0.5)
-Result
     moles = 0.4195 
2.- Calculate the mass of acetic acid using proportions and cross multiplications
                    60.05 g ----------------------- 1 mol
                         x        ----------------------- 0.4195 moles
                         x = (0.4195 x 60.05) / 1
                         x = 25.19 g
3.- Conclusion
25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M
                 
 
        
             
        
        
        
Answer:
Explanation:
There's no equation attached. What equation is it? 
 
        
                    
             
        
        
        
I need a a picture or the question
        
             
        
        
        
At 3.5s the distance would be 10.85
Find 1/4th of 2.00 and add that to 6.2