Answer:
10mm
Explanation:
According to Hooke's law which states that "the extension of an elastic material is directly proportional to the applied force provided the elastic limit is not exceeded. Direct proportionality there means, increase/decrease in the force leads to increase/decrease in extension.
Mathematically, F = ke where;
F is the applied force
k is the elastic constant
e is the extension
from the formula k = F/e
k = F1/e1 = F2/e2
Given force of 1N indents the spring inwards by 2mm, this means force of 1N generates extension of 2mm
Let F1 = 1N e1 = 2mm
The extension that will be produced If force of 5N is applied to the string is what we are looking for. Therefore F2 = 5N; e2= ?
Substituting this values in the formula above we have
1/2=5/e2
Cross multiplying;
e2 = 10mm
This shows that we must have dent it by 10mm before it pushes outwards by a 5N force
Answer:
They are the only joints that can do 360 degrees and rotate with their own axis. But, because of its free-moving, it is prone to any dislocation compared to other movable joints.
Explanation:
Answer:
Blank One: I'm not certain but I'd assume it's either sound or energy.
Blank Two: Louder
Explanation:
volume is controlled by how much energy is put in an area per a unit of time, so the more energy in one area for a unit of time, the louder the sound will come out.
Sorry I couldn't give the best explanation!
Answer:
(c) 3 m/s;
Explanation:
Moment of inertia of the fish eels about its long body as axis
= 1/2 m R ² where m is mass of its body and R is radius of transverse cross section of body .
= 1/2 x m x (5 x 10⁻² )²
I = 12.5 m x 10⁻⁴ kg m²
angular velocity of the eel
ω = 2 π n where n is revolution per second
=2 π n
= 2 π x 14
= 28π
Rotational kinetic energy
= 1/2 I ω²
= .5 x 12.5 m x 10⁻⁴ x(28π)²
= 4.8312m J
To match this kinetic energy let eel requires to have linear velocity of V
1 / 2 m V² = 4.8312m
V = 3.10
or 3 m /s .
Answer:
The rated current for the 600V side is I = 100 A and the rated current for the 120 V side is 500 A.
Explanation:
For standard transformers they step up or down the level of voltage while maintaning the power output (ideally). So the same power output should be seen on both sides, since the equation for apparent power is P = V*I we can solve for I on both sides and find the rated current. So we have:
600 V side:
P = V*I
I = P/V = (60*10^3)/600 = 100 A
120 V side:
P = V*I = (60*10^3)/120 = 500 A