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siniylev [52]
3 years ago
6

Determine the slit width that produces a diffraction pattern with the 2nd dark fringe at 6.2mm from the central fringe. The scre

en distance is 1.25m and the light wavelength is 600nm.
Physics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

d= 0.242 mm

Explanation:

Slit width (d ) = ?

Screen distance ( D ) = 1.25 m

Wave length of light λ = 600 nm

Distance of n the dark fringe from centre

= n λ D / d

Here n = 2

so

6.2\times10^{-3}=\frac{2\times600\times10^{-9}}{d}

d=\frac{1500\times10^{-6}}{6.2}

d= 0.242 mm

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A 1232 kg car moving north at 25.6 m/s collides with a 2028 kg car moving north at 17.5 m/s . They stick together. In what direc
Citrus2011 [14]

Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

<u>Given the following data;</u>

Mass of car A = 1232 Kg

Velocity of car A = 25.6 m/s

Mass of car B = 2028 Kg

Velocity of car B = 17.5m/s

First of all, we would solve for momentum;

Momentum = mass × velocity

Momentum, M1 = 1232 × 25.6

Momentum, M1 = 31539.2 Kgm/s

Momentum, M2 = 2028 × 17.5

Momentum, M2 = 35490 Kgm/s

Now, let's find the resultant momentum using the Pythagoras theorem;

R² = M1² + M2²

R² = 31539.2² + 35490²

R² = 994721136.6 + 1259540100

R² = 2254261237

Taking the square root of both sides, we have

Resultant momentum, R = 47479.06 Kgm/s

To find the direction;

Angle = tan¯¹(M1/M2)

Angle = tan¯¹(31539.2/35490)

Angle = tan¯¹(0.89)

<em>Angle = 41.7° Northeast.</em>

To find the speed;

R = (M1 + M2)Vr

47479.06 = (31539.2 + 35490)Vr

47479.06 = 67029.2Vr

Vr = 47479.06/67029.2

<em>Vr = 7.08m/s</em>

6 0
3 years ago
Write your answer to the question below.
ElenaW [278]

Answer:

Hi... Potential energy is converted to kinetic energy and kinetic energy is converted to potential energy

8 0
3 years ago
A 1.5m wire carries a 3 A current when a potential difference of 74 V is applied. What is the resistance of the wire?
Allisa [31]

Answer:

24.7 ohms

Explanation:

Given in the question,

electric current = 3 A

potential difference = 74 V

Using ohm's law

<h3>V = IR</h3>

R = V/I

<em>here,</em>

<em>R = resistance of wire</em>

<em>V = potential difference</em>

<em>I = electric current</em>

<em />

plug value in the formula

R = 74/3

R = 24.7 ohms

Therefore, the resistance of the wire is, 24.7 ohms

4 0
3 years ago
A 100-watt lightbulb radiates energy at a rate of 100 J/s. (The watt, a unit of power, or energy over time, is defined as 1 J/s.
fomenos

Answer:

N=2.18\cdot 10^{20}photons/s

Explanation:

The energy of a photon is: E=h\nu=h\frac{c}{\lambda} when h is the Planck constant.

h=6.63\cdot 10^{-34}Js    

c=3.8\cdot 10^{8}m/s

Then, we calculate the energy of a photon with a wavelength equal to 550 nm.

E= 4.58\cdot 10^{-19}J

To find the number of photons we can use this equation:

N=\frac{P}{E}=\frac{100}{4.58\cdot 10^{-19}}=2.18\cdot 10^{20} photons/s

Have a nice day!

7 0
3 years ago
A child looked at
fgiga [73]
The answer to your question is A.
4 0
2 years ago
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