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bagirrra123 [75]
3 years ago
7

What is the relationship between SI units and CGS unit of work ?

Physics
1 answer:
VashaNatasha [74]3 years ago
8 0
Work SI unit = joule = N*m= [kg]*[m/s^2] *[m] = kg * m^2/s^2

Work cgs unit = erg =  [g][cm/s^2][cm] = g*cm^2 / s^2

Then 1 kg * m^2 / s^2 * [1000 g/kg] * [100cm/m]^2 = 10,000,000 g*cm^2/s^2

The relation is 1 joule = 10,000,000 erg or 1 erg = 10^-7 joule
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Earth orbits the sun once every
Karo-lina-s [1.5K]

Answer:1 trip around the earth is an angular displacement of 2*pi

3.6525*10^2 days

I

Explanation:24 h/1 day * 3.600*10^3 s/1h = 3.156*10^7 s

Angular speed = angular displacement / time

Angular speed = 2*pi rads / 3.156*10^7 s = 1.9910*10^-7 rad/s

3 0
3 years ago
A skier is skiing down a slope on the mountain.
uysha [10]

The mechanical energy isn't conserved. Some energy is lost to friction.

Option A.

<h3><u>Explanation:</u></h3>

The mechanical energy is defined as the energy of a body which it achieves by virtue of its position and velocity. The mechanical energy are of two types - potential energy and kinetic energy. The potential energy is the energy of the body which it achieves by means of its relative position and is directly proportional to the height of the body from its relative plane. Whereas the kinetic energy of the body is achieved by virtue of its velocity and is directly proportional to the square of velocity of the body.

As the mountaineer is skiing down the slope of a mountain, the potential energy of the person is gradually changing into his kinetic energy. Had it been in an ideal situation, the potential energy lost would have been just equal to the kinetic energy gained by the person. But there's friction which opposes the speed of the body and reduces the velocity. Thus the kinetic energy will be lost to some extent and the energy won't be conserved.

4 0
3 years ago
This time particle A starts from rest and accelerates to the right at 65.5 cm/s
FrozenT [24]

Answer:

t = 4 s

Explanation:

As we know that the particle A starts from Rest with constant acceleration

So the distance moved by the particle in given time "t"

d = v_i t + \frac{1}{2}at^2

d = 0 + \frac{1}{2}(65.5)t^2

d_1 = 32.75 t^2 cm

Now we know that B moves with constant speed so in the same time B will move to another distance

d_2 = 44 \times t

now we know that B is already 349 cm down the track

so if A and B will meet after time "t"

then in that case

d_1 = 349 + d_2

32.75 t^2 = 349 + 44 t

on solving above kinematics equation we have

t = 4 s

4 0
3 years ago
6 Fig. 6.1 is a full-scale diagram that represents a sound wave travelling in air
Oxana [17]

From  the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

<h3>What is the frequency of a wave?</h3>

The frequency of a wave is the number of complete oscillation per second completed by a wave.

Frequency is related to wavelength and speed by the following formula:

  • Frequency = velocity/wavelength

Velocity of sound in air = 330 m/s

The measured wavelength = 5.0 cm = 0.05 m

Frequency = 330/0.05 = 6660 Hz

Therefore, based on the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

Learn  more about frequency of sound at: https://brainly.in/question/15373132
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7 0
2 years ago
Which statement is correct?
miv72 [106K]
'A' is correct. B, C, and D are false statements.
5 0
3 years ago
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