All categories

1 year ago

6 Fig. 6.1 is a full-scale diagram that represents a sound wave travelling in air

Physics

1 answer:

Oxana [17]1 year ago

7 0

From the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

<h3>What is the frequency of a wave?</h3>

The frequency of a wave is the number of complete oscillation per second completed by a wave.

Frequency is related to wavelength and speed by the following formula:

Frequency = velocity/wavelength

Velocity of sound in air = 330 m/s

The measured wavelength = 5.0 cm = 0.05 m

Frequency = 330/0.05 = 6660 Hz

Therefore, based on the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

Learn more about frequency of sound at: https://brainly.in/question/15373132
#SPJ1

You might be interested in

A man kicks the 150-g ball such that it leaves the ground at an angle of 60° and strikes the ground at the same elevation a dist

egoroff_w [7]

Answer:

$313.92\ \text{m/s}$

$47.088\ \text{kg m/s}$

Explanation:

m = Mass of ball = 150 g

$\theta$ = Angle of kick = $60^{\circ}$

$x$ = Displacement of ball in x direction = 12 m

Range of projectile is given by

$x=\dfrac{u\sin^2\theta}{2g}\\\Rightarrow u=\dfrac{2xg}{\sin^2\theta}\\\Rightarrow u=\dfrac{2\times 12\times 9.81}{\sin^260^{\circ}}\\\Rightarrow u=313.92\ \text{m/s}$

The velocity of the ball instantly after the man kicks the ball is $313.92\ \text{m/s}$

Impulse is given by

$J=mu\\\Rightarrow J=0.15\times 313.92\\\Rightarrow J=47.088\ \text{kg m/s}$

The impulse of his foot on the ball is $47.088\ \text{kg m/s}$ .

3 0

2 years ago

What is the relationship between the horizontal and vertical components of velocity for a projectile launched

quester [9]

Answer: The horizontal velocity of a projectile is constant (a never changing in value. The vertical velocity of a projectile changes by 9.8 m/s each second.

Explanation: I hope that helped!

3 0

2 years ago

How many miles of MgCI2 are there in 339g of compound?

harkovskaia [24]

I'm going to answer this by using rounded numbers for the atomic masses. You need only go back and put the numbers in from your periodic table. My answers will be close, but not what you should get.

Find the Molar Mass of MgCl2

Mg = 24 grams

2Cl = 2 * 35.5 = 71 grams

Total = 95 grams

Find the mols in 339 grams

1 mole = 95 grams

x mol = 339

Solve

339 = 95x Divide by 95

339/95 = x

x = 3.67 mols Answer

4 0

2 years ago

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 350 newtons stretches a sprin

Bingel [31]

Answer:

Explanation:

350 N force stretches the spring by 30 cm

spring constant K = 350 / 0.30 = (350 / 0.3) N / m

To calculate work done by a spring force we proceed as follows

spring force when the spring is stretched by x = Kx

This force is variable so work done by it can be calculated by integration

Work done by it in stretching from x₁ to x₂

W = ∫ F dx

= ∫ Kx dx with limit from x₁ to x ₂

= 1/2 K ( x₂² - x₁² )

Putting the given values of x₁ = 0.50 m , x₂ = 0.8 m

Work done

= 1/2 x (350 / 0.3)x ( 0.80² - 0.50² )

= 227.50 J

5 0

2 years ago

Someone please help me answer this !!!

Elan Coil [88]

Answer:

I think its C sorry if it's wrong

7 0

2 years ago