1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alekssandra [29.7K]
2 years ago
14

6 Fig. 6.1 is a full-scale diagram that represents a sound wave travelling in air

Physics
1 answer:
Oxana [17]2 years ago
7 0

From  the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

<h3>What is the frequency of a wave?</h3>

The frequency of a wave is the number of complete oscillation per second completed by a wave.

Frequency is related to wavelength and speed by the following formula:

  • Frequency = velocity/wavelength

Velocity of sound in air = 330 m/s

The measured wavelength = 5.0 cm = 0.05 m

Frequency = 330/0.05 = 6660 Hz

Therefore, based on the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

Learn  more about frequency of sound at: https://brainly.in/question/15373132
#SPJ1

You might be interested in
A capacitor with a very large capacitance is in series with a capacitor that has a very small capacitance. what can we say about
Misha Larkins [42]
<span>A capacitor with a very large capacitance is in series with a capacitor
that has a very small capacitance.

The capacitance of the series combination is slightly smaller than the
capacitance of the small capacitor. (choice-C)

The capacitance of a series combination is

             1 / (1/A + 1/B + 1/C + 1/D + .....) .

If you wisk, fold, knead, and mash that expression for a while,
you find that for only two capacitors in series, (or 2 resistors or
two inductors in parallel), the combination is   

             (product of the 2 individuals) / (sum of the individuals)  .

In this problem, we have a humongous one and a tiny one.
Let's call them  1000  and  1 .
Then the series combination is

           (1000 x 1) / (1000 + 1)

        =       (1000) / (1001)

        =         0.999 000 999 . . . 

which is smaller than the smaller individual.

It'll always be that way.   </span>
5 0
3 years ago
Mr. Rudman drives his race car for 4 hrs at 150<br> miles/hr. How far will he travel?
Lilit [14]
150*4=600
So the answer is 600
7 0
3 years ago
Is this true of false <br> Apples and Onions taste the same if you plug your nose?
xxMikexx [17]
I think yes because you won’t be able to smell
7 0
3 years ago
Un cuerpo de masa m tiene una velocidad v. si la masa del cuerpo se incrementa al triple de su valor original y la velocidad se
serg [7]
Urrrrrrrr nope now clue at all
5 0
3 years ago
Bodies weighing 1 kilogram and 5 kilograms lie on a smooth horizontal surface. If a traction force of 0.6 N acts on another 5 kg
natima [27]

0.6/5,1,5

so calculate it

not so sure though

6 0
3 years ago
Other questions:
  • A 0.134-A current is charging a capacitor that has square plates 6.00 cm on each side. The plate separation is 4.00 mm. (a) Find
    7·1 answer
  • If an automobile engine delivers 42.0 hp of power, how much time will it take for the engine to do 6.20 â 105 j of work? (hint:
    5·1 answer
  • Three solid, uniform, cylindrical flywheels, each of mass 65.0 kg and radius 1.47 m, rotate independently around a common axis t
    12·1 answer
  • "For an object moving at a constant speed, we would expect to see a position graph with a
    15·1 answer
  • Starting from a pillar, you run 200 m east (the + x-direction) at an average speed of 5.0 m/s and then run 280 m west at an aver
    10·1 answer
  • Applications of machine ​
    10·1 answer
  • Conversion fraction 1$=4q, how many are in 20$
    10·2 answers
  • 24. Compare and contrast the 'Big Bang Theory' with the 'Creation Model for the origin of the
    14·1 answer
  • WILL MARK BRAINLIST!!! only for correct answer<br> NEED CORRECT ANSWER ASAPPP
    7·1 answer
  • What is the best definition of
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!