<h3>
Answer:a) Distance= 240m. b) Displacement= 90m. c) Average Speed= 5
. d) Average Velocity= 1.875 </h3>
Explanation:
a) Distance ➤ (80+50+70+40) m. ➤ Distance= 240m.
b) Displacement ➤ (50+40)m. ➤ Displacement= 90m
c) Average Speed ➤ Total distance travelled/total time taken
➤ 240/48
➤ 5
d) Average Velocity ➤ Total displacement/total time taken
➤ 90/48
➤ 1.875
C because If it still moving in a circle it’s not going to change.
Acceleration = force/mass
1/4
s=ut+1/2at^2
0*4+1/2*1/4*4^2
1/2*1/4*16
1/2*4
=2
Answer:
The time taken by the rock to reach the ground is 0.569 seconds.
Explanation:
Given that,
A student throws a rock horizontally off a 5.0 m tall building, s = 5 m
The initial speed of the rock, u = 6 m/s
We need to find the time taken by the rock to reach the ground. Using second equation of motion to find it. We get :
So, the time taken by the rock to reach the ground is 0.569 seconds. Hence, this is the required solution.
Answer:
They both experienced the same force as they weigh the same amount
Newtonian physics
Explanation:
