Answer:
Respiration
Explanation:
The act of breathing, simple as that!
Hope this helped!!
They are performed in the JEJUNUM
First structure is CH₃-CH₃. It is an alkane with two carbon atoms hence it is called ethane.
Second structure is CH₃-CH₂-CH₂-CH₃. It is an alkane with four carbon atoms hence it is called butane.
Third structure is CH₄. It is an alkane with one carbon atom hence it is called methane.
Fourth structure is CH₃-CH₂-CH₃. It is an alkane with three carbon atoms hence it is called propane.
You need to use the formula--> P1V1= P2V2 (Boyles's law)
P1= 14 bar
V1= 312 mL
P2= ?
V2= 652 mL
now we plug the values into the formula.
(14 x 312) = (P2x 652)
P2= (14 x 312)/ 652= <span>6.70 bar</span>
Answer:
- 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s)
Explanation:
The<em> standard enthalpy of formation </em>of a substance is the change in enthalpy that happens when one mole of the substance is formed from the elements in their standard states.
Thus, to calculate the standard state of formation of a compound you must:
- 1. Identify the elements that form the compound
- 2. Identify the standard form of each element
- 3. Set the equation to form one mole of the compound, which may require to use fractional coefficients for some of the elements.
Applying that to our compound K₂SO₃
<u>1. Elements:</u>
- potassium, K;
- sulfur, S; and
- oxygen, O.
<u />
<u>2. Standard forms of the elements:</u>
- potassium: solid, K(s)
- sulfur: solid, octatomic molecules, S₈ (s)
- oxygen: diatomic gas, O₂(g)
<u>3. Reaction:</u>
- K(s) + S₈ (s) + O₂(g) → K₂SO₃ (s)
Balance, keeping one mole of K₂SO₃. You will need to use fractional coefficients for some elements:
- 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s) ← answer
