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Sergeeva-Olga [200]
2 years ago
10

The name of an alcohol side chain is known as an alkoxy group. True or false?

Chemistry
1 answer:
mylen [45]2 years ago
6 0
By itself, i don’t think so.

though, paired with a hydrogen bond, it is.

If i’m wrong, please feel free to let me know :)
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Which state has a tundra and sub-arctic climate? a. Alaska c. North Dakota b. Montana d. None of the above Please select the bes
Sergio039 [100]
I would say Alaska because that's where most of the subarctic climate is found.
4 0
3 years ago
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How many moles are in 564 grams of Copper
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63.55 is how many miles are in 564 grams of copper
4 0
3 years ago
Which property of water makes it helpful to use in car radiators?
Nezavi [6.7K]
The correct answer is<span> C) Water takes long to heat and cool down than other liquids.

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5 0
2 years ago
30. The density of an unknown gas at 27°C and 2 atm pressure is equal with density of N2 gas at
Zanzabum

Answer:

Molar mass of the unknown gas is 64.6 g/mol

Explanation:

Let's think this excersise with the Ideal Gases Law.

We start from the N₂. At STP conditions we know that 1 mol of anything occupies 22.4L.

We apply: P . V = n . R . T

5 atm . V = 1 mol . 0.082 . 325K

V = (1 mol . 0.082 . 325K) / 5 atm = 5.33 L

It is reasonable to say that, if we have more pressure, we may have less volume.

As this is the volume for 1 mol of N₂, our mass is 28 g. Then, the density of the nitrogen and the unknown gas is 28 g/5.33L = 5.25 g/L

Our unknown gas has, this density at 27°C and 2 atm.

If we star from this, again: 1 mol of any gas occupy 22.4L at STP, we can calculate the volume for 1 mol at those conditions:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

1 atm . 22,4L / 273K = 2 atm . V₂ / 300K

Remember that the value for T° is Absolute (T°C + 273)

[ (1 atm . 22.4L / 273K) . 300K] / 2 atm = V₂ → 12.3L

This is the volume for 1 mol of the unknown gas at 2 atm and 27°C

We use density to determine the mass: 12.3 L . 5.25 g/L = 64.6 g

That's the molar mass: 64.6 g/mol

6 0
2 years ago
A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
azamat

Answer:

Age=2.52*10^9 years

Explanation:

To determine the age, we need to know how much U have become Pb, so first we have to calculate the Pb moles present in a sample:

n_{Pb}=\frac{0.337g}{206g/mol}=0.00164 mol

n_{U}=\frac{1 g}{238g/mol}=0.0042 mol

The percentage of U degradation:

P=\frac{n_{Pb}}{n_{Pb}+n_{U}}

P=\frac{0.00164}{0.00164+0.0042}=0.28

Assuming that the life time is linear:

Age=\frac{4.5*10^9 years}{0.5 life time}*0.28 life time

Age=2.52*10^9 years

4 0
3 years ago
Read 2 more answers
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