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Minchanka [31]
3 years ago
9

The reactants of a reaction are 2AgClO3 and Na2CO3. According to the law of

Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

The answer is "Option B"

Explanation:

Law:

In the law of the conservation of matter, states the volume of matter throughout the process remains constant. In any particular case, it is closed to the movement of matter.  It is mostly on conservation of energy means, that the total mass of the products should consider the sum of the mass, which is the reactant of the event of chemical processes.

Reaction:

2AgClO_3+ Na_2CO_3= Ag_2CO_3+Na_2ClO_3

In the above equation when we react to 2AgClO_3 from the Na_2CO_3, it will give Ag_2CO_3 \ \ \text{and} \ \ Na_2ClO_3. that's why option b is correct.

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Which of the following will have a larger radius than zinc ? Gallium (Ga) Magnesium (Mg) Aluminum (Al) Strontium (St)
oksian1 [2.3K]

Answer:

Strontium (St)

Explanation:

The atom that will have a larger radius than zinc is strontium, Sr.

Atomic radius is defined as the half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.

  • Across the period atomic radii decreases progressively due to the increase in nuclear charge.
  • Down a group atomic radii increase progressively due to the successive shells of electrons being added.
  • Since strontium satisfies the criteria, it has the larger atomic radius.
7 0
3 years ago
True or False. Index Fossils are formed from organisms that were alive for short period of geologic time, are extinct, had hard
NemiM [27]

Answer:

Index fossil, any animal or plant preserved in the rock record of the Earth that is characteristic of a particular span of geologic time or environment.

Explanation:

True

6 0
2 years ago
Read 2 more answers
Consider the reaction pathway graph below.
Alex17521 [72]
Hello!

The reaction that the graph represents is A. Exothermic because Hrxn=-167 kJ

To calculate Hrxn we apply the following equation:

Hrxn=Hproducts-Hreagents=-625kJ-(-458kJ)=-167kJ

Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction releases energy in the form of heat and that the reaction is exothermic.

Have a nice day!
6 0
3 years ago
The ionic radius for Na+ is 0.097 ηm and for Cl- is 0.181 ηm, the absolute value of the charge for each ion is 1.6x10-19 C, ε_o=
Vanyuwa [196]

Answer:

B = (2.953 × 10⁻⁹⁵) N.m⁹

Explanation:

At equilibrium, where the distance between the two ions (ro) is the sum of their ionic radii, the force between the two ions is zero.

That is,

Fa + Fr = 0

Fa = - Fr

Fa = (|q₁q₂|)/(4πε₀r²)

Fr = -B/(r^n) but n = 9

Fr = -B/r⁹

(|q₁q₂|)/(4πε₀r²) = (B/r⁹)

|q₁| = |q₂| = (1.6 × 10⁻¹⁹) C

(1/4πε₀) = k = (8.99 × 10⁹) Nm²/C²

r = 0.097 + 0.181 = 0.278 nm = (2.78 × 10⁻¹⁰) m

(k|q₁q₂|)/(r²) = (B/r⁹)

(k × |q₁q₂|) = (B/r⁷)

B = (k × |q₁q₂| × r⁷)

B = [8.99 × 10⁹ × 1.6 × 10⁻¹⁹ × 1.6 × 10⁻¹⁹ × (2.78 × 10⁻¹⁰)⁷]

B = (2.953 × 10⁻⁹⁵) N.m⁹

6 0
3 years ago
Four springs are stretched to the same distance from the equilibrium position. The spring constants are listed in the table. A 2
svp [43]

Answer:

The correct option is;

X, W, Y, Z

Explanation:

The parameters given are;

Spring (S),         Spring Constant (N/m)

      W,                   24

      X,                    35

      Y,                    22

      Z,                    15

The equation for elastic potential energy, E_e, is E_e = 0.5 \times k \times x^2

The above equation can also be written as E_e =\dfrac{1}{2}  \times k \times x^2

Where:

k = The spring constant in (N/m)

x = The spring extension

Therefore, since the elastic potential energy, E_e, of the spring is directly proportional to the spring constant, k, we have the springs with higher spring constant will have higher elastic potential energy, E_e, therefore the correct order is as follows;

X > W > Y > Z

9 0
3 years ago
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