Oxidation of nitrogen to nitrogen oxide in the channel of a lightning:
N₂ + O₂ = 2NO
oxidation of natural nitrogen oxide and of nitrogen oxide of combustion gases to nitrogen dioxide:
2NO + O₂ = 2NO₂
nitrogen dioxide reaction with moisture of air or rain water:
4NO₂ + O₂ + 2H₂O = 4HNO₃
The procedure for this is the next one:
moles CaC2 = 485 g/64.1 g/mol=7.57
<span>moles H2O = 2 x 7.57 =15.1 </span>
<span>mass H2O = 15.1 mol x 18.02 g/mol=272.8 g
</span>
Answer:
.14L or 140mL
Explanation:
This is a classic plug-n-chug problem. Your textbook probably goes over this formula as
. M stands for molarity of the given substance, and V stands for the volume that the substance occupies.
Simply plug in the values that you're given, like so:


After completing the algebra portion and solving for the unknown, you will be left with x = .14L, which is the volume required to neutralize 30mL of 7M NaOH.
Milk mixture and heterogeneous