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Sholpan [36]
1 year ago
15

. A girl of mass 35 kg and boy of mass 25 kg are connected by a light rope. They move horizontally in a skating rink. A second r

ope is attached to the girl and with this second rope, she is pulled by a force of 300 N. The magnitude of their acceleration is ?
Physics
1 answer:
Dmitriy789 [7]1 year ago
3 0

The magnitude of the acceleration of the boy and the girl is 5 m/s².

<h3>What is the acceleration of the boy and the girl?</h3>

The magnitude of the acceleration of the boy and the girl is determined by applying Newton's second law of motion as shown below.

F = ma

where;

  • F is the net force on the boy and girl = T
  • m is total mass of the boy and the girl = m₁ + m₂
  • a is the common acceleration of the boy and the girl

substitute the given parameters and solve for the common acceleration of the boy and the girl

a = T/(m₁+ m₂)

a = (300 N) / (35 kg + 25 kg)

a = 5 m/s²

Learn more about acceleration here: brainly.com/question/14344386

#SPJ1

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an astronaut on an eva has wandered dangerously far away from the shuttle. she has also exhausted all the fuel in her jet pack.
V125BC [204]

The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:

  • Throwing the thruster away from the ship.

The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum  is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.

Initial instant. Astronaut and thrust together.

        p₀ = 0

Final moment. The astronaut now the thruster in the opposite direction of the ship.

       m_f = m v + M v '

where m is propellant mass and M the astronaut mass.

As the moment is preserved.

       0 = m v + M v ’

      v ’= - \frac{m}{M} \ v  

We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.

The magnitude of the velocity is given by the relationship between the masses.

In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:

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5 0
2 years ago
a 1500 kg car accelerates uniformly from rest to 10.0 meters per secound in 3.0 secound .what is the work done on the car in thi
zubka84 [21]

Answer:

The work done on the car is, W = 75,000 J

The power delivered by the engine, P = 25,000 watts

Explanation:

Given,

The mass of the car, m = 1500 Kg

The initial velocity of the car, u = 0

The final velocity of the car, v = 10 m

The time duration of the travel, t = 3 s

Using the first equation of motion

                     v = u + at

                     a = (v - u) / t

Substituting the given values in the above equation

                    a = (10 - 0) / 3

                       = 3.33 m/s²

Using the second equations of motion

                      s = ut + 1/2 at²

                         = 0 + 0.5 x 3.33 x 3²

                         = 15 m

The force exerted by the car

                         F = m x a

                            = 1500 Kg x 3.33 m/s²

                            = 5000 N

The work done by the car,

                          W = F x S

                               = 5000 N x 15 m

                               = 75,000 J

Hence, the work done on the car is, W = 75,000 J

The power delivered by the engine,

                            P = W / t

                                = 75,000 J / 3 s

                                 = 25,000 watts

The power delivered by the engine, P = 25,000 watts

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Answer: You could dissolve it by heating it back up, then just cooling it down again.

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