Question

. A girl of mass 35 kg and boy of mass 25 kg are connected by a light rope. They move horizontally in a skating rink. A second rope is attached to the girl and with this second rope, she is pulled by a force of 300 N. The magnitude of their acceleration is ?

Answer 1

The magnitude of the acceleration of the boy and the girl is 5 m/s².

What is the acceleration of the boy and the girl?

The magnitude of the acceleration of the boy and the girl is determined by applying Newton's second law of motion as shown below.

F = ma

where;

• F is the net force on the boy and girl = T
• m is total mass of the boy and the girl = m₁ + m₂
• a is the common acceleration of the boy and the girl

substitute the given parameters and solve for the common acceleration of the boy and the girl

a = T/(m₁+ m₂)

a = (300 N) / (35 kg + 25 kg)

a = 5 m/s²

Learn more about acceleration here: brainly.com/question/14344386

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