. A girl of mass 35 kg and boy of mass 25 kg are connected by a light rope. They move horizontally in a skating rink. A second r ope is attached to the girl and with this second rope, she is pulled by a force of 300 N. The magnitude of their acceleration is ?
1 answer:
The magnitude of the acceleration of the boy and the girl is 5 m/s².
<h3>What is the acceleration of the boy and the girl?</h3>
The magnitude of the acceleration of the boy and the girl is determined by applying Newton's second law of motion as shown below.
F = ma
where;
F is the net force on the boy and girl = T m is total mass of the boy and the girl = m₁ + m₂ a is the common acceleration of the boy and the girl
substitute the given parameters and solve for the common acceleration of the boy and the girl
a = T/(m₁+ m₂)
a = (300 N) / (35 kg + 25 kg)
a = 5 m/s²
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