Answer:
Explanation:
We can use basic trig in a right triangle to solve this problem. Let the x component of the force be . We have the following equation:
Answer: a) 335.8 μm; b) keeping the same radius, the new has double potential, V=1340V so if teh radius is also double the potentail is the same (V=670V).
Explanation: In order to explain this problem we have to consider the potential given for sphere respect to infinity ( V=0) in the form:
V=k*Q/R the we have
R=k*Q/V= 9*10^9*25*10^-12/670=335.8 *10^-6 m
When two drop join to form a single drop (considering with the same radius) we have:
V=k*2Q/R
So the new V is double the original,
V=9*10^9*2*25*10^-12/335.8*10^-6=1340V
if the final single drop has a 2R of radius so
V=k*2Q/2R= 670 V
It has the same original potential.
Answer:
0 J
Explanation:
From the diagram below; we would notice that the Force (F) = Tension (T)
Also the angle θ adjacent to the perpendicular line = 90 °
The Workdone W = F. d
W = Fd cos θ
W = Fd cos 90°
W = Fd (0)
W = 0 J
Hence the force is perpendicular to the direction of displacement and the net work done in a circular motion in one complete revolution is = 0
Answer:
38Kgm/s
Explanation:
Momentum (p) = mass (m) × velocity (v)
Total momentum is the sum of all the momenta of each object in a system. That is:
Total momentum = {m1v1} + {m2v2}
Where;
m1 = mass of ball 1 = 5kg
v1 = velocity of ball 1 = 4m/s
m2 = mass of ball 2 = 6kg
v2 = velocity of ball 2 = 3m/s
Total momentum = {5 × 4} + {6 × 3}
Total momentum = {20} + {18}
Total momentum = 38Kgm/s