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PtichkaEL [24]
4 years ago
14

A truck accidentally rolls down a driveway for 8.0\,\text m8.0m8, point, 0, start text, m, end text while a person pushes agains

t the truck with a force of 850\,\text N850N850, start text, N, end text to bring it to a stop. What is the change in kinetic energy for the truck?
Physics
1 answer:
gavmur [86]4 years ago
5 0

Answer:

Explanation:

According to work energy theorem

change in kinetic energy of truck = work done against it

work done against it = force x displacement

= - 850 x 8 = 6800 J

change in kinetic energy of truck = - 6800 J .

energy will be reduced by 6800 J

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Two moles of neon gas at 25oC and 2.0 atm is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. F
bazaltina [42]

Answer:

The end temperature is 174 °C

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, being:

  • P= 2 atm
  • V=?
  • n= 2 moles
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 25 °C= 298 °K

and replacing:

2 atm*V= 2 moles* 0.082 \frac{atm*L}{mol*K} *298 K

you get:

V=\frac{2 moles* 0.082\frac{atm*L}{mol*K}  *298 K}{2 atm}

V= 24.436 L

Now, two moles of neon gas is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. Then you know:

  • P= 1 atm
  • V= 3*24.436 L=73.308 L
  • n= 2 moles
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= ?

Replacing:

1 atm*73.308 L= 2 moles* 0.082 \frac{atm*L}{mol*K} *T

Solving:

T=\frac{1 atm*73.308 L}{2 moles* 0.082\frac{atm*L}{mol*K}}

T= 447 °K= 174 °C (being 0°C=273 °K)

<u><em>The end temperature is 174 °C</em></u>

5 0
3 years ago
Pleassseeee help meeeee
lukranit [14]

Answer:

maybe the rear wheel axel rusted not sure

7 0
3 years ago
A labor push a crate through 12m and 720 J of work .The magnitude of force was
Harrizon [31]

Answer:

<h2>60 N</h2>

Explanation:

The magnitude of the force can be found by using the formula

f =  \frac{w}{d}  \\

w is the workdone

d is the distance

From the question we have

f =  \frac{720}{12}  = 60 \\

We have the final answer as

<h3>60 N</h3>

Hope this helps you

6 0
3 years ago
A(n) ____ follows a curved path in space around Earth. No options.. I'm confused..
lesya [120]
It's a projectile near the earth under the influence of gravity only.
6 0
4 years ago
An electron is accelerqated in the uniform field betwen two parallel charged oplates. The separation of the plates is 1.20 cm
marysya [2.9K]

Answer:

The speed of electron is 8.7\times10^{6}\ m/s

Explanation:

Given that,

Separation of the plate = 1.20 cm

Suppose the field is E=1.80\times10^{4}\ N/C.

If the electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.

What the speed does it leave the hole?

We need to calculate the acceleration

Using formula of electric force

F = qE

ma=qE

a=\dfrac{qE}{m}

We need to calculate the speed of electron

Using equation of motion

v^2=u^2+2as

v^2=2as

Put the value of acceleration in the formula

v^2=2\times\dfrac{qE}{m}\times s

Put the value into the formula

v^2=2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}

v=\sqrt{2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}}

v=8.7\times10^{6}\ m/s

Hence, The speed of electron is 8.7\times10^{6}\ m/s

7 0
3 years ago
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