Answer: 7.07 grams
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.052 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of give = 1 mole of
Thus 0.052 moles of give =
of
Mass of
Thus 7.07 g of will be produced from the given masses of both reactants.
682mL
Explanation:
Given parameters:
Initial volume of air = 600mL
Initial temperature = 20°C
Final temperature = 60°C
Unknown:
Final volume = ?
Solution:
To solve this problem, we apply Charles's law';
Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "
Mathematically;
V₁ is the initial volume of air
T₁ is the initial temperature of air
V₂ is the final volume of air
T₂ is the final temperature of air
To proceed in solving this problem, we need to convert the given temperature to Kelvin;
T K = 273 + T°C
T₁ = 273 + 20 = 293K
T₂ = 273 + 60 = 333K
now input the parameters;
V₂ = 682mL
learn more:
Gas laws brainly.com/question/2438000
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