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a_sh-v [17]
3 years ago
9

What advice did Planck ignore when he was a student,and how did it impact future discoveries

Chemistry
1 answer:
yan [13]3 years ago
5 0

Answer:

A PROFESSOR WARNED HIM NOT TO GO INTO PHYSICS. Not long after the 16-year-old Planck got to the University of Munich in 1874, physics professor Philipp von Jolly tried to dissuade the young student from going into theoretical physics. Jolly argued that other scientists had basically figured out all there was to know.

Explanation:

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What is the difference between hydrophilic and hydrophobic?
Nataliya [291]
Hydrophilic - attracted to water
Hydrophobic - resists water
7 0
2 years ago
3
solniwko [45]

Answer:

A

Explanation:

With the given choices, A would be correct for this question.  But, both liquids and gases have particles that are far apart so that they can fill their containers.

7 0
3 years ago
500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.
jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL

Putting values in above equation, we get:

0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M

Hence, the concentration of diluted solution is 0.16 M

5 0
3 years ago
The process of __________ turns water vapor to liquid.
Elanso [62]
I belive this is called condensation.
hope this helps!
4 0
3 years ago
If 45.8 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced? 2KClO3 → 2KCl + 3O2
natta225 [31]
To do this problem, we must first look at the balanced chemical equation for the decomposition of potassium chlorate: 

<span>2KClO3 --> 2KCl + 3O2 </span>

<span>We can take the given amount of grams, and use the molar mass of KClO3 to convert to moles. Then, we can use the stoichiometric ratios to relate moles of KClO3 to moles of O2. </span>

<span>(39.09)+(35.45)+(3*15.99)= 122.51 g/ mol = molar mass of KClO3 </span>
<span>45.8 g KClO3/ 122.51 g/ mol KClO3 = .374 moles KClO3 </span>
<span>.374 mol KClO3 *(3 moles O2/2 mol KClO3)= .560 moles O2 </span>

<span>Once we have moles of O2, we can convert to grams of O2. </span>

<span>(2*15.99)= 31.98 g/mol = molar mass of O2 </span>
<span>(.560 moles O2) (31.98 g/mol)= 17.91 g O2 </span>


<span>Hope this helps :)</span>
3 0
3 years ago
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