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a_sh-v [17]
3 years ago
9

What advice did Planck ignore when he was a student,and how did it impact future discoveries

Chemistry
1 answer:
yan [13]3 years ago
5 0

Answer:

A PROFESSOR WARNED HIM NOT TO GO INTO PHYSICS. Not long after the 16-year-old Planck got to the University of Munich in 1874, physics professor Philipp von Jolly tried to dissuade the young student from going into theoretical physics. Jolly argued that other scientists had basically figured out all there was to know.

Explanation:

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The volume of a gas at 17.5 psi decreases from 1.8L to 750mL. What is the new pressure of the gas in arm?
Maurinko [17]

Answer:

P₂ = 2.88 atm

Explanation:

Given data:

Initial volume of gas = 1.8 L

Final volume = 750 mL

Initial pressure = 17.5 Psi

Final pressure = ?

Solution:

We will convert the units first:

Initial pressure = 17.5  /14.696 = 1.2 atm

Final volume = 750 mL ×1L/1000L = 0.75 L

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.2 atm × 1.8 L =  P₂  ×0.75 L

P₂ = 2.16 atm. L/ 0.75 L

P₂ = 2.88 atm

4 0
3 years ago
In ____________, electrons are gained by atoms and lost by others
Nat2105 [25]
In ions atoms lose and gain electrons
3 0
3 years ago
Read 2 more answers
What is the percent composition of the u.s quarter, which has the mass of 5.670g
Vitek1552 [10]
The percent composition of each element can be calculated as follows:
% composition = (mass of element / total mass) * 100

The total mass of the quarter is given to be 5.670 grams
Mass of Cu = 5.198 grams
Mass of Ni = 0.472 grams

Substitute in the above equation to get the mass percentage of each element as follows:
% of Cu = (5.198/5.670) * 100 = 91.675%
% of Ni = (0.472/5.670) * 100 = 8.325%
6 0
3 years ago
Draw the most stable resonance structure for the intermediate in the electrophilic aromatic bromination of aniline, anisole, and
ASHA 777 [7]

Answer:

Here's what I get

Explanation:

(a) Intermediates

The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).

(b) Relative Stabilities

The relative stabilities decrease in the order shown.

N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.

(c) Relative reactivities

The relative reactivities would be

C₆H₅-NH₂ >  C₆H₅-OCH₃ > C₆H₅-NHCOCH₃

4 0
3 years ago
A. what is the hybridization of the central atom in cse2?
elixir [45]

The orbital hybridization of the central carbon atom in CSe2 is sp.

In chemical bonding, atomic orbitals may be combined to form appropriate hybrid orbitals suitable for bonding. The orbitals that combine during hybridization must be close enough in energy.

In the compound Cse2, carbon is the central atom bonded to two selenium atoms. The carbon atom in CSe2 is sp hybridized.

Learn more about orbital hybridization:  brainly.com/question/1869903

4 0
2 years ago
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