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3 years ago

What advice did Planck ignore when he was a student,and how did it impact future discoveries

Chemistry

1 answer:

yan [13]3 years ago

5 0

Answer:

A PROFESSOR WARNED HIM NOT TO GO INTO PHYSICS. Not long after the 16-year-old Planck got to the University of Munich in 1874, physics professor Philipp von Jolly tried to dissuade the young student from going into theoretical physics. Jolly argued that other scientists had basically figured out all there was to know.

Explanation:

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Solution that is used as the titrant (put in buret) in this experiment. Substance that gives the light pink end point in this ex

Alja [10]

E is the correct answer

6 0

3 years ago

An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th

Vladimir [108]

<u>Answer:</u> The molarity of $NO_3^-$ ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute $(Cu(NO_3)_2.6H_2O)$ = 15.6 g

Molar mass of $(Cu(NO_3)_2.6H_2O)$ = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

$\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M$

As, 1 mole of $(Cu(NO_3)_2.6H_2O)$ produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of $NO_3^-$ ions = (2 × 0.153) = 0.306 M

Hence, the molarity of $NO_3^-$ ions in the solution is 0.306 M

3 0

3 years ago

2. At STP, a sample of gas occupies 24.5 mL. Calculate the volume of this gas at a

Law Incorporation [45]

Answer:

11.7 ml = V

Explanation: Here

6 0

2 years ago

Calculate the number of oxygen atoms in 2.00 moles of Mn2O7

cluponka [151]

First you should know that there is seven oxygen atoms in one Mn2O7
So
2.00 moles of Mn2O7 contain 14.00 moles of oxygen...
Then you multiply this no. with Avagadro no....
from formula
Number of moles= no. of particles/avagadro's no..
14.00×6.02×10²³=84.28 atoms of oxygen...

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3 years ago

What are the products in this chemical reaction?

Alja [10]

A. CO2 + 2H2O + ENERGY

THIS IS THE ANSWER

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3 years ago