Hthe heat required  to change the temperfature  of 100 grams of water  from 25 to 55 c is calculated as below
Q(heat) = M(mass) x C(specific heat capacity) x delta T(change  in temperature)
M= 100 grams
C= 4.18 j/g/c
delta T= 55-25 =30c
Q=100 g x4.814 j/g/c x  30c = 12552  joules
        
             
        
        
        
The answer will be, so3 since s only need two electrons to complete its octet
        
             
        
        
        
<h3>
Answer:</h3>
6.68 g MgSO₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Aqueous Solutions</u>
- Molarity = moles of solute / liters of solution
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
0.965 L
0.0575 M
<u>Step 2: Identify Conversions</u>
Molar Mass of Mg - 24.31 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol
<u>Step 3: Find MgSO₄</u>
- Substitute [M]:                     0.0575 M = x / 0.965 L
- Isolate <em>x</em>:                              0.055488 mol MgSO₄ = x
- Rewrite:                               x = 0.055488 mol MgSO₄
<u>Step 4: Convert</u>
<u /> = 6.67959 g MgSO₄
 = 6.67959 g MgSO₄
<u>Step 5: Check</u>
<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>
6.67959 g MgSO₄ ≈ 6.68 g MgSO₄