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Art [367]
3 years ago
13

Potassium and fluorine are both halogens?​

Chemistry
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

false, Potassium and fluorine are not halogens.

only fluorine here is halogen.

potassium is an alkali earth metal it doesn't comes under category of halogens, but fluorine

is a non metal which comes under halogen family.

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What is the molarity of a strong acid solution with a pH of 3?
Anna35 [415]

Answer:

Since HCl is a strong acid, it completely ionizes, and the pH of HCl in solution can be found from the concentration (molarity) of the H+ ions, by definition equal to 0.100 M. (The conjugate base of the acid, which is the chloride ion Cl–, would also have a concentration of 0.100 M.) The pH is thus –log(0.100) = 1.000.

Explanation:

6 0
3 years ago
Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta
Sergeu [11.5K]

Answer:

The half-reaction for the oxidation of the manganese in MnCO_3(s) to MnO_2(s).:

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+

Explanation:

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Let us say the medium in which reaction is taking place is an acidic medium. And balancing in an acidic mediums done as;

Step 1: Balance all the atom beside oxygen and hydrogen atom;

MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Manganese and carbon are balanced.

Step 2: Balance oxygen atom adding water on the required side:

MnCO_3+H_2O+H_2O\rightarrow MnO_2(s)+HCO_3^{-}

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}

Step 3: Now balance hydrogen atom by adding hydrogen ion on the required side:

MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+

6 0
3 years ago
Calculate the mass, in grams, of Al(OH)3 required for this reaction:
AVprozaik [17]

Answer:

Mass = 28.08

Explanation:

Given data:

Mass of Al₂O₃ = 21.8 g

Mass of water = 9.7 g

Mass of Al(OH)₃ = ?

Solution:

Chemical equation:

2Al(OH)₃   →   Al₂O₃ + 3H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 9.7 g/ 18 g/mol

Number of  moles = 0.54 mol

Number of moles of Al₂O₃:

Number of moles = mass/molar mass

Number of moles = 21.8 g/ 101.96 g/mol

Number of  moles = 0.21 mol

Now we will compare the moles of Al(OH)₃ with  Al₂O₃ and H₂O.

                          Al₂O₃       :          Al(OH)₃

                             1            :              2

                         0.21          :         2×0.21 = 0.42 mol

                         H₂O          :            Al(OH)₃

                            3            ;             2

                          0.54        :        2/3×0.54 = 0.36 mol

Mass of Al(OH)₃:

Mass = number of moles × molar mass

Mass = 0.36 mol × 78 g/mol

Mass = 28.08 g

3 0
3 years ago
In a particular electroplating process, the metal being plated has a +4 charge. If 861.8 C of charge pass through the cell, how
Xelga [282]

Answer: 2.2326\times 10^{-3} moles

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

The metal being plated has a +4 charge, thus the equation will be:

M^{4+}+4e^-\rightarrow M

4\times 96500C of electricity deposits = 1 mole of metal

Thus 861.8 C of electricity deposits =\frac{1}{4\times 96500}\times 861.8=2.2326\times 10^{-3} moles of metal

Thus 2.2326\times 10^{-3} moles of metal should be plated

3 0
3 years ago
A 0.1 m salt solution has a ph = 7.0 at 25 degrees
vfiekz [6]
RbOH + HBr = RbBr + H₂O
NaOH + HClO₄ = NaClO₄ + H₂O
rubidium bromide RbBr and sodium perchlorate NaClO₄ are formed by the strong basis and the strong acid
pH=7
8 0
3 years ago
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