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3 years ago

13

What happens when one freezes salt water?

1 answer:

abruzzese [7]3 years ago

8 0

The answer is B.

The solvent is the part of solution in which the solute is dissolved. Salt, being the solute, makes it harder for water to crystallize into a formal lattice, requiring a lower temperature to trigger the freezing into an irregular structure.

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How many parts per million of lead is found in 250 ml of water if there is 1.30g of lead in the water? 1ml=1g

SSSSS [86.1K]

Answer:

5200 ppm

Explanation:

As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.

Given in the question,

Water = 250 ml = 250 g

Lead = 1.30 g

So,

ppm of Lead = $\frac{Lead}{Water} \times 10^6$ = $\frac{1.30}{250} \times 10^6$ = 5200 ppm

So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.

6 0

2 years ago

What amount of carbon dioxide (in moles) is produced from the reaction of 2.24 moles of ethanol with excess oxygen?

algol13

Answer : The amount of carbon dioxide produced is, 197.12 grams.

Explanation : Given,

Moles of ethanol = 2.24 mole

Molar mass of carbon dioxide = 44 g/mole

The balanced chemical reaction will be,

$C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O$

First we have to calculate the moles carbon dioxide.

From the balanced chemical reaction, we conclude that

As, 1 mole of ethanol react to give 2 moles of carbon dioxide

So, 2.24 mole of ethanol react to give $2\times 2.24=4.48$ moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2$

$\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g$

Therefore, the amount of carbon dioxide produced is 197.12 grams.

8 0

2 years ago

A stock solution of ammonia in water is 28 wt% NH3. The Formal Weight (FW) of NH3 is 17.03 g/mol). The solution density at room

weqwewe [10]

Answer:

[NH₃] = 14.7 mol/L

Explanation:

28 wt% is a type of concentration that indicates that 28 g of ammonia is contained in 100 g of solution.

Let's determine the amount of ammonia:

28 g . 1 mol / 17.03g = 1.64 moles of NH₃

You need to consider that, when you have density's data it is always referred to solution:

Mass of solution is 100 g, let's find out the volume

0.90 g/mL = 100 g /V

V = 100 g / 0.90mL/g → 111.1 mL

We convert the volume to L → 111.1 mL . 1 L/1000mL = 0.1111 L

mol/L = 1.64 mol/0.1111L → 14.7 M

mol/L = M → molarity a sort of concentration that indicates the moles of solute in 1L of solution

4 0

2 years ago

A mixture of benzene and toluene has a total vapor pressure at 25°C of 45.06 mmHg. What is the partial pressure of benzene in th

SashulF [63]

Answer:

I just need points so ignore my answer and thanks

3 0

3 years ago

When steam turns a turbine, what kind of energy is being manifest?

mihalych1998 [28]

Answer: mechanical

Explanation:

its a big mechanicale thing

6 0

3 years ago

Read 2 more answers