Explanation:
For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.
For example, 
, 
and 
all these compounds contain an electronegative atom attached to hydrogen atom.
Therefore, these pure compounds will exhibit hydrogen bonding.
Thus, we can conclude that out of the given options , and are the pure compounds which will exhibit hydrogen bonding.
Answer:
go back through your lesson or google a what causes a what heat transfer rate
Explanation:
Hello
So the molar mass of a Hydrogen molecule is 2. If you have 10 grams of Hydrogen molecules, you have 5 moles<span> of Hydrogen molecules (10 moles of Hydrogen atoms). Avogadro's number is 6.0225x10^23. This means that </span>one mole<span> of a substance has that many particles.
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Have a nice day
Answer:
24.47 L
Explanation:
Using the general gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = 0.0821 Latm/molK
T = temperature (K)
According to the provided information in this question,
P = 1.0 atm
V = ?
n = 1 mol
T = 25°C = 25 + 273 = 298K
Using PV = nRT
V = nRT ÷ P
V = 1 × 0.0821 × 298 ÷ 1
V = 24.465 ÷ 1
V = 24.465
V = 24.47 L
<span>Total mass = 2.75g
Mass % of Mg = 1.0g x 100/2.75g = 36.36 %
Mass % of O = 1.75g x 100/2.75g = 63.64 %
Mol of Mg = 36.36/24 = 1.515
Mol of O = 63.64/16 = 3.977
Ratio of Mol of Mg and O in the substance = (1.515 : 3.977) x 2 = 3 : 8
The empirical formula of substance is Mg3O8</span>
