Answer:
54 days
Explanation:
We have to use the formula;
0.693/t1/2 =2.303/t log Ao/A
Where;
t1/2= half-life of phosphorus-32= 14.3 days
t= time taken for the activity to fall to 7.34% of its original value
Ao=initial activity of phosphorus-32
A= activity of phosphorus-32 after a time t
Note that;
A=0.0734Ao (the activity of the sample decreased to 7.34% of the activity of the original sample)
Substituting values;
0.693/14.3 = 2.303/t log Ao/0.0734Ao
0.693/14.3 = 2.303/t log 1/0.0734
0.693/14.3 = 2.6/t
0.048=2.6/t
t= 2.6/0.048
t= 54 days
Answer:
2 circles one proton and one nucleon.draw quarks within each. strong nuclear force within protons between quarks and residual strong force between proton and nucleon (up,up,down in proton)
Explanation:
The temperature , <u>165 degree F</u> should soup that contains cooked beef be reheated for hot-holding.
Food should reach a temperature serving 135°F before it can be opened in the restaurant and warmed for hot holding. Within two hours, quickly reheat the food. If food is being served right away, it can be served anywhere at temperature as long that it as it was cooked and chilled appropriately.
TCS food must be totally chilled to 41°F or even below in 6 hours after being thoroughly cooled between 135°F to 70°F in 2 hours. Within four hours, TCS food made with ingredients at room temperature needs to be chilled to 41°F or lower.
Therefore, the temperature , <u>165 degree F</u> should soup that contains cooked beef be reheated for hot-holding.
To know more about temperature
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The answer
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH - is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =<span>0.001 62
and for a strong basis, pH can be calculated as pH = 14 + log </span>[ OH -]
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79
finally pH = 14 -2.79 = 11.20
