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3 years ago

14

a lab is performed to do the study of pH and heat on the function of the catalase enzyme found in carrot plants. what would be c

onsidered the independent variable(s) in this lab

1 answer:

ad-work [718]3 years ago

3 0

It would be the ph and heat

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Imagine a planet that has a similar atmospheric pressure to Earth (760 mmHg) but different concentrations of gases in its atmosp

RUDIKE [14]

Answer:

76 mmHg is the partial pressure of oxygen on this new planet.

Explanation:

Atmospheric pressure on air on earth = 760 mmHg

On an unknown planet :

Oxygen makes up 10% of the atmosphere.

The mole fraction of oxygen gas can be written as = $\chi_1=\frac{10}{100}=0.1$

Carbon dioxide makes up 15% of the atmosphere.

The mole fraction of carbon dioxide gas can be written as = $\chi_2=\frac{15}{100}=0.15$

Nitrogen makes up the remaining 75% of the atmosphere.

The mole fraction of nitrogen gas can be written as = $\chi_1=\frac{75}{100}=0.75$

Atmospheric pressure of air on unknown planet,p= 760 mmHg (given)

Partial pressure of gases can be calculated by the help o Dalton's law of partial pressure:

Partial pressure of oxygen gas :

$p_1=p\times \chi_1$

$p_1=760 mmHg\times 0.1=76 mmHg$

Partial pressure of carbon dioxide gas :

$p_2=p\times \chi_2$

$p_2=760 mmHg\times 0.15=114 mmHg$

Partial pressure of nitrogen gas :

$p_3=p\times \chi_3$

$p_3=760 mmHg\times 0.75=570 mmHg$

8 0

3 years ago

A twenty-eight-liter volume of gas contains 11 g methane, 1.5-gram nitrogen and 16-gram carbon dioxide. Determine partial pressu

GREYUIT [131]

Based on Dalton's Law, for a mixture of gases, the total pressure is the sum of the partial pressure of each gas.

Partial pressure (p) of each gas is related to the total pressure (P) as follows:

p = X * P----------(1)

where X is the mole fraction of that gas

X = moles of a particular gas/total number of moles of all gases in the mixture--------------(2)

Step 1: Calculate the moles of each gas

Mass of methane, CH4 = 11 g

Mass of nitrogen, N2 = 1.4 g

Mass of carbon dioxide, CO2 = 16 g

# moles of CH4 = 11 g/16 gmol-1 = 0.6875

# moles of N2 = 1.4/28 = 0.05

# moles of CO2 = 16/44 = 0.3636

Total moles = 0.6875+0.05+0.3636 = 1.1011

Step2: Calculate mole fractions of each gas

Based on equation (2)

X(CH4) = 0.6875/1.1011 = 0.6244

X(N2) = 0.05/1.1011 = 0.0454

X(CO2) = 0.3636/1.1011 = 0.3302

Step 3: Calculate the total pressure

Based on ideal gas equation:

PV = nRT

given that;

V = 28 L

n = total moles = 1.1011

R = gas constant = 0.0821 Latm/mol-K

Since temp T is not given, let us consider room temperature of 25 C = 25 + 273 = 298 K

Now, P = nRT/V = 1.011*0.0821*298/28 = 0.962 atm

Step 3: Calculate partial pressures

Based on equation:

p(CH4) = 0.6244*0.962 atm = 0.601 atm

P(N2) = 0.0454*0.962 atm = 0.044 atm

P(CO2) = 0.3302*0.962 atm = 0.318 atm

4 0

3 years ago

Help i don't know how to find the percentage yield in stoichiometry!

Harrizon [31]

Sorry I honestly have no idea I just want my points

3 0

3 years ago

How is 0.00069 written in scientific notation?

vfiekz [6]

6.9 x 10^-4 would be .00069 written in scientific notation

4 0

3 years ago

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How much electric energy does a 40 W light bulb use if it is left on for 12 hours?

OlgaM077 [116]

480 hrs of electricity

3 0

3 years ago