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2 years ago

How will the temperature of the water be affected by the dissolving of the lithium oxide?

Chemistry

1 answer:

lesantik [10]2 years ago

6 0

Answer:

i can Help you but iam using my phone so typing is really hectic. reach me via app on +254743503332

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Which energy source from a reservoir would provide affordable, abundant electricity for a factory? solar panels wind turbines ga

Sunny_sXe [5.5K]

The energy source from a reservoir would provide affordable, abundant electricity for a factory is a hydroelectric power plant; option D.

<h3>What is energy?</h3>

Energy is the ability to do work.

Energy generating plants may either use wind, water or solar energy to produce electrical energy.

The most abundant source of energy from a reservoir is hydroelectric power plant.

Therefore, the energy source from a reservoir would provide affordable, abundant electricity for a factory is a hydroelectric power plant.

In conclusion, hydroelectric power plants are reservoirs of abundant energy supply.

Learn more about hydroelectric power plants at: brainly.com/question/3406557

#SPJ1

7 0

2 years ago

The following information was recorded by a student team working to prepare nickel sulfate. Plan: Prepare NiSO4 by reacting NiO

mixas84 [53]

Answer:

The options e and d are correct.

Explanation:

Mass of NiO = 7.5 g

Moles of NiO = $\frac{7.5 g}{74.69 g/mol}=0.10 mol$

Moles of sulfuric acid = n

Volume of sulfuric acid ,V= 50 mL = 0.050 L

Molarity of sulfuric acid ,M = 6 mol/L

$n=M\time V=6mol/L\times 0.050 L =0.3 mol$

$NiO + H_2SO_4\rightarrow NiSO_4 + H_2O$

According to reaction, 1 mole of NiO reacts with 1 mole of sulfuric acid.

Then 0.10 moles of NiO reacts with :

$\frac{1}{1}\times 0.10 mol/=0.10 mol$ of sulfuric acid.

As we can see that sulfuric acid is in excess amount, so the amount of the product will depend upon amount of NiO.

According to reaction, 1 mole of NiO gives with 1 mole of $NiSO_4$ .

Then 0.10 moles of NiO wil give :

$\frac{1}{1}\times 0.10 mol/=0.10 mol$ of $NiSO_4$ .

Molar mass of $NiSO_4$ = 154.75 g/mol

Mass of 0.10 moles of $NiSO_4$ :

= 154.75 g/mol × 0.10 mol = 15.475 g

Theoretical mass of $NiSO_4$ = 15.475 g

Experimental yield of $NiSO_4$ = 17.4 g

Percentage yield :

$\Yield=\frac{\text{Experimental mass}}{\text{Theoretical mass}}\times 100$

Percentage yield of $NiSO_4$ :

$\Yield=\frac{17.4}{15.475 g}\times 100=112\%$

Moles of $NiSO_4.6H_2O$ = 262.85 g/mol × 0.10 mol = 26.285 g

Experimental yield of $NiSO_4.6H_2O$ = 17.4 g

Percentage yield of $NiSO_4.6H_2O$ :

$\Yield=\frac{17.4}{26.285 g}\times 100=66.2\%$

3 0

3 years ago

Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin

DanielleElmas [232]

Answer:

74.4 ml

Explanation:

C₆H₈O₇(aq) + 3NaHCO₃(s) => Na₃C₆H₅O₃(aq + 3CO₂(g) + 3H₂O(l)

Given 15g = 15g/84g/mol = 0.1786mole Sodium Bicarbonate

From equation stoichiometry 3moles NaHCO₃ is needed for each mole citric acid or, moles of citric acid needed is 1/3 of moles sodium bicarbonate used.

Therefore, for complete reaction of 0.1786 mole NaHCO₃ one would need 1/3 of 0.1786 mole citric acid or 0.0595 mole H-citrate.

The question is now what volume of 0.8M H-citrate solution would contain 0.0595mole of the H-citrate? This can be determined from the equation defining molarity. That is => Molarity = moles solute / Liters of solution

=> Volume (Liters) = moles citric acid / Molarity of citric acid solution

=> Volume needed in liters = 0.0.0595 mole/0.80M = 0.0744 Liters or 74.4 ml

6 0

3 years ago

When a -COOH group replaces a hydrogen in a hydrocarbon the result is a/an ____.

jonny [76]

Carboxylic acid...........

7 0

3 years ago

Suppose that 2.14 grams of H2SO4 is mixed with enough water to make 225 mL of solution. Determine the Molarity (M) of the soluti

Alik [6]

Answer:

0.0970 M

Explanation:

Remember this equation:

mol/M x V

Convert it so that you can get M.

M=mol/V

Convert the 2.14 grams of H2SO4 into mols

=0.0218

Convert mL to L

225/1000

=0.225

Plug it in.

0.0218/0.225

=0.0970 M

6 0

3 years ago