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melamori03 [73]
1 year ago
10

How will the temperature of the water be affected by the dissolving of the lithium oxide?

Chemistry
1 answer:
lesantik [10]1 year ago
6 0

Answer:

i can Help you but iam using my phone so typing is really hectic. reach me via app on +254743503332

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If a neutral compound is composed of carbon and hydrogen and you know that it has exactly 2 carbons connected by a double bond,
Oksanka [162]

Answer: 4 hydrogens

Explanation:

This is what the structure will look like C=C. Remember that it's important that all structures have a complete octet. As it looks right now each carbon is sharing 4 valence electrons so each needs 2 more bonds to hydrogen complete its octet.

4 0
2 years ago
Read 2 more answers
Select each process that shows a physical change. Select all that apply.
erica [24]

Answer:

Chopping wood logs

A pot of water o a grate over a burning fire

Explanation:

Physical change is easily reversible. Burning/combustion is a chemical process where substances react rapidly with oxygen: this is usually irreversible.

The marshmallow, roasted food and burned wood all undergo combustion and hence are tagged chemical changes.

Explanation:

5 0
2 years ago
Read 2 more answers
Im posting seperate questions so just answer this one
vredina [299]
On the lab the text is kind of too far zoomed out so u can’t really read it it’s like blurry
6 0
2 years ago
Which of the following represents the correct ranking in terms of increasing boiling point? A. n-butane < 1-butanol < diet
bonufazy [111]

Answer:

The answer to your question is: letter E

Explanation:

Normally, the correct order of boiling points is:

                     Alcohols > Ketones > Ether > Alkane

Then

A. n-butane < 1-butanol < diethyl ether < 2-butanone

B. n-butane < 2-butanone < diethyl ether < 1-butanol

C. 2-butanone < n-butane < diethyl ether < 1-butanol

D. n-butane < diethyl ether < 1-butanol < 2-butanone

E. n-butane < diethyl ether < 2-butanone < 1-butanol

     (- 1°C)     <    34.6°C         <  79.64°C      <  117.7°C

6 0
3 years ago
what volume of N2 is required to convert 5.0L of hydrogen gas to ammonia? assume that all gases are at the same temperature and
____ [38]

Answer:

Approximately 1.7\; {\rm L}.

Explanation:

Nitrogen {\rm N_{2}}\, (g) reacts with hydrogen {\rm H_{2}}\, (g) at a 1:3 ratio to produce ammonia {\rm NH_3}\, (g):

{\rm N_{2}}\, (g) + 3\; {\rm H_{2}}\, (g) \to 2\; {\rm NH_{3}}\, (g).

The ratio between the coefficient of {\rm N_{2}}\, (g) and the coefficient of {\rm H_{2}}\, (g) is:

\begin{aligned}\frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}.

Under the ideal gas assumptions, the same ratio would apply to the volume of {\rm N_{2}}\, (g) and {\rm H_{2}}\, (g) in this reaction:

\begin{aligned}\frac{V({\rm N_{2}})}{V({\rm H_{2}})} = \frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}.

\begin{aligned}V({\rm N_{2}})= \frac{1}{3}\, V({\rm H_{2}})\end{aligned}.

Given that V({\rm H_{2}}) = 5.0\; {\rm L}:

\begin{aligned}V({\rm N_{2}}) &= \frac{1}{3}\, V({\rm H_{2}}) \\ &= \frac{1}{3}\times 5.0\; {\rm L} \\ &\approx 1.7\; {\rm L}\end{aligned}.

(Rounded to 2 significant figures.)

5 0
2 years ago
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