The following illustration <span>contains the stoichiometric quantities of the reactants for this reaction.
</span><span>In the Haber process, nitrogen (N2) and hydrogen (H2) are directly combined to form ammonia (NH3). </span><span>The reaction is as follows :
N</span>
+
=
Therefore, 1 mole of nitrogen is equivalent to 3 moles of Hydrogen
Answer:
The total pressure of three gases is 837.56 mmHg.
Explanation:
The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:
PT = PA + PB
This relationship is due to the assumption that there are no attractive forces between the gases.
In this case, the total pressure can be calculated as:
PT= 2.67 mmHg + 45.69 mmHg + 789.6 mmHg
Solving:
PT= 837.56 mmHg
<em><u>The total pressure of three gases is 837.56 mmHg.</u></em>
Answer:
0.095 moles of O₂ are left over.
Explanation:
First of all, state the balanced reaction:
2NO + O₂ → 2NO₂
We determine moles of each reactant:
20.2 g . 1mol / 30g = 0.673 moles of NO
13.8g . 1mol / 32g = 0.431 moles of oxygen
Oxygen is the excess reactant. Let's see.
For 2 moles of NO I need 1 mol of O₂
Then, for 0.673 moles of NO I may use (0.673 .1) /2 = 0.336 moles
I have 0.431 moles of O₂ and I only need 0.336 mol. According to reaction, stoichiometry is 2:1.
In conclussion, the moles of excess reactant that will be left over:
0.431 - 0.336 = 0.095 moles
When n=2 we have 8electrons, when n=4 l=1 we have 6electrons, when n=6 l=2 m-l=-1 qe have 1electron
