You could put carbon or oxygen
Answer:
The Gibbs free energy is -2997.83 kJ mol-1.
Explanation:
The change in Gibbs free energy of the reaction can be calculated using the formula.
WHere R = Gas constant = 8.314KJ/Kmol
T = the temperature of the reaction in Kelvin = (37.0 + 273) = 310K
K = Raio of molar concentration of the two reactants = 1.6/0.5 = 3.2
Therefore,
Therefore the Gibbs free energy is -2997.83 kJ mol-1.
The negative sign indicates that the reaction is spontaneous.
Answer: Option (b) is the correct answer.
Explanation:
Porosity means the ease with which a fluid can pass through between a rock or cracks etc.
If particles of a soil are flat and even if they are sorted then there will rarely be any space available for fluid or water to pass through it.
If soil particles are round in shape and are sorted then there will be space available for the fluid to pass through it. Hence, this type of soil will be most porous.
Similarly, if soil particles are round but are unsorted then there will be less space available as compared to sorted particles. This is because particles are placed randomly so, somewhere there will be much less space and somewhere there will be large space available. As a result, soil will not be most porous.
If soil particles are flat and unsorted then there will also be less space available for the fluid to pass through it. Thus, soil will be less porous.
Hence, we can conclude that out of the given options, soil B - round, sorted particles is the most porous.
6. You must divide the mass by it’s molar mass to give you the total amount of moles within that piece. This will give you approx 0.05mol. You can now multiply this value by Avagadros constant which gives you 2.93 x 10^22 atoms. I would expect gold to have less atoms as it’s molar mass is higher than that of silvers, meaning that less atoms would be required to equal the same mass
Answer:
42.8
Explanation:
Let's consider the following reaction at equilibrium.
CO(g) + 2 H₂(g) ⇌ CH₃OH(g)
The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
The concentration equilibrium constant for this reaction is: