The molality of calcium chloride (CaCl2) in an aqueous solution is 2.46 m. What is mole fraction of the solute?
1 answer:
Given that CaCl2 = 2.46 m
Therefore 2.46 mole of CaCl2 present in 1.00 g of solution
Mass of 2.46 mole CaCl2= number of mole * molar mass
= 2.46 mole * 110.98 g/mol
= 273.01 g
Mass of water or solvent = mass of solution – mass of solute
= 1000 g -273.01 g
= 726.99 g
Mole of water = amount in g / molar mass
= 726.99 g/18.02 g/ mole
= 40.34 moles
Mole fraction of CaCl2 = number of mole of CaCl2 / total moles
= 2.46 /2.46+40.34
= 2.46/42.8
= 0.057
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