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77julia77 [94]
2 years ago
10

Please show steps Thanks

Chemistry
1 answer:
Llana [10]2 years ago
8 0

Answer:

2.5M

Explanation:

First calculate the gram-formula mass of CaCO3 (add up the mass of each element in the compound)

40.1 + 12.01 + 16(3) = 100.11

Now use the mole calculation equation on Table T and plug in the numbers

(Keep in mind that 25 is the given mass)

25/100.11 = 2.497 or 2.5M

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Aspartame is a sweetner that is 160 times sweeter than sucrose (table sugar) when dissolved in water. The molecular formula of a
NikAS [45]

Answer:

  • <u><em>294.307 g/mol</em></u>

Explanation:

The first question for this statment is:

  • <em>Calculate the gram-formula-mass of aspartame. </em>

<em />

<h2>Solution</h2>

The chemical formula is:

        C_{14}H_{18}N_2O_5 .

The <em>gram-formula-mass </em>is calculated adding the masses for all the atoms in the molecular formula:

Atom       Number of atoms      Atomic mass       Total mass

                                                            g/mol            g/mol

C                     14                              12.011              14 × 12.011 = 164.154

H                     18                              1.008              18 × 1.008 = 18.144

N                      2                              14.007             2 × 14.007 = 28.014

O                      5                              15.999             5 × 15.999 = 79.995

                                                                                ===================

                                                            Total            294.307 g/mol

Answer: 294.307 g/mol

6 0
3 years ago
Which unit can be used to express the rate of a reaction?
Ugo [173]
<span>A) mL / s

This is the amount of milliliters per second</span>
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lys-0071 [83]

D. a new technology.
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3 years ago
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Rank the following solutions in order of increasing acidity (least acidic to most acidic): I: [H3O+] = 1x10−5 II: [OH−] = 1x10−1
kozerog [31]

Answer: option C) II < III < I

i.e [OH−] < [H3O+] < I

Explanation:

First, obtain the pH value of I and II, then compare both with III.

For I

Recall that pH = -log (H+)

So pH3O = -log (H3O+)

= - log (1x10−5)

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For II

pOH = - log(OH-)

= - log(1x10−10)

= 9

For III

pH = 6

Since, pH range from 1 to 14, with values below 7 to be acidic, 7 to be neutral, above 7 to be alkaline: then, 9 < 6 < 4

Thus, the following solutions from least acidic to most acidic is II < III < I

6 0
3 years ago
To how much water should 100 ml of 18m sulfuric acid be added to prepare a 1.5m solution
SashulF [63]

Answer:

Take 100 ml of a 18 molar solution. The total number of moles is (1 liter/1000 ml) 100 ml 18 moles is 1.8 moles.

1.5 moles in 1 liter so If 1.1 liters of water is added, the total volume is 1.2 liters and 1.8 moles are dissolves in it. 1.8 moles/ 1.2 liters is 1.5 moles per liter.

5 0
3 years ago
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