Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.
2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O
1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O
Empirical formula
H2SO4
I think its becuse the shoreline is shalow water that is warmed by the sun? ...... I may be rong
Answer:
3.824 atm
Explanation:
From the ideal gas equation
P = mRT/MW × V
m is mass of testosterone = 12.9 g
R is gas constant = 82.057 cm^3.atm/mol.K
T is temperature of benzene solution = 298 K
MW is molecular weight of testosterone = 288.40 g/mol
V is volume of benzene solution = 286 ml = 286 cm^3
P = 12.9×82.057×298/288.4×286 = 3.824 atm
