Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.
<u>Moon #1:</u> (1.262 days)² / (2.346 x 10^4 km)³
<u>Moon #2:</u> (orbital period)² / (9.378 x 10^3 km)³
If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.
Cross multiply the proportion:
(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³
Divide each side by (2.346 x 10^4)³:
(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³
= 0.1017 day²
Orbital period = <u>0.319 Earth day</u> = about 7.6 hours.
Explanation:
Law of conservation of momentum states that in an isolated system when two objects collide with each other then total momentum before and after the collision is equal.
Thus, we can conclude that the law of conservation of momentum states that the total momentum of interacting objects does not change. This means the total momentum before a collision or explosion is equal to the to momentum after a collision or explosion.
Please solve it ,,,,,,,,,,................................
fredd [130]
Answer:
the distance covered by the body in 5th second =u+a(n- 1/2)=7+4(5- 1/2)
=7+4×9/2
=7+18
=25m
-40 c = -40 f but k would be 233.15
Answer:
.....different temperatures
Explanation:
heat is a form of energy that is transfered from a body of high temperature to a body of low temperature....Cannot happen if the two bodies have the same temperature(thermal equilibrium)
