Answer : The standard enthalpy of reaction is, -318.618 kJ
Explanation :
Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28reactant%29%5D)
The equilibrium reaction follows:

The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(n_{(MA_2)}\times \Delta H^o_f_{(MA_2)})+(n_{(HX)}\times \Delta H^o_f_{(HX)})]-[(n_{(HA)}\times \Delta H^o_f_{(HA)})+(n_{(MX_2)}\times \Delta H^o_f_{(MX_2)})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%28n_%7B%28MA_2%29%7D%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28MA_2%29%7D%29%2B%28n_%7B%28HX%29%7D%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28HX%29%7D%29%5D-%5B%28n_%7B%28HA%29%7D%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28HA%29%7D%29%2B%28n_%7B%28MX_2%29%7D%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28MX_2%29%7D%29%5D)
We are given:

Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times -63.958)+(2\times -449.579)]-[(2\times -357.05)+(1\times 69.602)]=-318.618kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20-63.958%29%2B%282%5Ctimes%20-449.579%29%5D-%5B%282%5Ctimes%20-357.05%29%2B%281%5Ctimes%2069.602%29%5D%3D-318.618kJ)
Thus, the standard enthalpy of reaction is, -318.618 kJ
Answer:
12. 2 protons and 2 neutrons
13. decreased by 2
14. Energy
15. None
16. I believe is also none
17. None
Sorry but its about 3: 52 am and a bit sleepy.
Hope these are good answers for you!
Explanation:
To calculate the wavelength of this radiation if the SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission process in the cesium atom, the wavelength is one cycle of radiation, and therefore the wavelength is 1/9192631770