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Olenka [21]
3 years ago
6

Are plant cells affected when water is scarce

Chemistry
1 answer:
boyakko [2]3 years ago
5 0
<span>Water is vital to the existence of plant life. Not only do plants use it to keep their cells from drying out, but they need water to move nutrients and raw materials throughout their systems to areas where photosynthesis and seed production take place. When water stress occurs, whether caused by drought or root impairment, many invisible processes are affected.</span>
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Which of the following statements is not accurate? A. At constant temperature, halving the number of gas particles in a given sp
vlabodo [156]
I suggest you to go with C !! it is absolutely wrong sentence !!

increasing the gas particles will increase the collision between them so !!

your answer is C !!
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Find the density of metal with a volume 4.0 cm and a mass of 8.0 grams.
olga_2 [115]
D=m/v

so,

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What term best defines the process that occurs when nuclei combine to produce a nucleus with more mass?
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A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
S_A_V [24]

Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =.?

Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

8 0
3 years ago
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