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goblinko [34]
2 years ago
6

A certain spring has a spring constant k1 = 660 N/m as the spring is stretched from x = 0 to x1 = 35 cm. The spring constant the

n changes to k2 = 250 N/m as the spring is stretched to x2 = 65 cm. From x2 = 65 cm to x3 = 89 cm the spring force is constant at F3 = 105 N.
Write an equation for the work done in stretching the spring from x1 to x2.
Calculate the work done, in joules, in stretching the spring from x1 to x2.
Calculate the work, in joules, necessary to stretch the spring from x = 0 to x3.
Physics
1 answer:
pantera1 [17]2 years ago
6 0

(a) The equation for the work done in stretching the spring from x1 to x2 is ¹/₂K₂Δx².

(b) The work done, in stretching the spring from x1 to x2 is 11.25 J.

(c) The work, necessary to stretch the spring from x = 0 to x3 is 64.28 J.

<h3>Work done in the spring</h3>

The work done in stretching the spring is calculated as follows;

W = ¹/₂kx²

W(1 to 2) = ¹/₂K₂Δx²

W(1 to 2)  =  ¹/₂(250)(0.65 - 0.35)²

W(1 to 2)  = 11.25 J

W(0  to 3) = ¹/₂k₁x₁² + ¹/₂k₂x₂² + ¹/₂F₃x₃

W(0  to 3) = ¹/₂(660)(0.35)² + ¹/₂(250)(0.65 - 0.35)² + ¹/₂(105)(0.89 - 0.65)

W(0  to 3) = 64.28 J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

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Explanation:

Given

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0-(u)^2=2\times a\times s

s_a=\frac{u^2}{2a}------1

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0-(2u)^2=2\times a\times s_b

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distance traveled by car B is four time of car A

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A circuit contains a 1.5v battery and a bulb with a 3 ohms resistance, calculate the current of the circuit
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What force acts on all objects, all the time on Earth?
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The force that acts on all objects, all the time on Earth is gravitational force.

The force that surface exert on an object perpendicularly is normal reaction.

<h3>What force acts on all objects, all the time on Earth?</h3>
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The force due to gravity on object's is calculated by applying Newton's second law of motion as follows;

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Will binoculars work properly if their prisms (assume n = 1.50) are immersed in water (nwater= 1.33)? assume that binoculars wor
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The binoculars will not work properly.

Please refer to the diagram attached.

Binoculars work on the principle of total internal reflection. The incident ray from air enters the prism through on face normally and it strikes the opposite face at an angle of 45°. The ray undergoes Total internal reflection if its critical angle is less than the angle of incidence,which , in this case is 45°.

The critical anglei_{c} is related to the refractive index of the material of glass μ as shown below.

\mu =\frac{1}{sini_c}

For a refractive index equal to 1.5, the critical angle is found as shown below.

sini_c=\frac{1}{\mu} \\ =\frac{1}{1.5} \\ =0.666

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