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Nastasia [14]
3 years ago
7

For problems 6-9, using the formula net Force = Mass• Acceleration calculate the net force on the object.

Physics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

Find answers below

Explanation:

Mathematically, force is given by the formula;

Force = mass * acceleration

Given the following data;

6. Mass = 8 kg

Acceleration = 2 m/s²

Force = 8 * 2

Force = 16 Newton

7. Mass = 5 kg

Acceleration = 2 m/s²

Force = 5 * 2

Force = 10 Newton

8. Mass = 8 kg

Acceleration = 8 m/s²

Force = 8 * 8

Force = 64 Newton

9. Mass = 200 kg

Acceleration = 3 m/s²

Force = 200 * 3

Force = 600 Newton

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5 0
2 years ago
A block of mass m is set sliding up along a frictionless ramp inclined at angle θ relative to horizontal. The angle of the ramp
timofeeve [1]

Answer:

1) h is constant

2) h is constant

3) h increases

Explanation:

"What happens to the height h as the angle θ is increased?"

The ramp is frictionless, so the initial kinetic energy is converted to the final gravitational potential energy.

½ mv² = mgh

½ v² = gh

h = v² / (2g)

Since v is constant, h is also constant.

"What happens to the height h if θ and v are kept the same, but the mass m of the block increases?"

As found above, h does not depend on the mass m, so h would remain constant.

"If we keep m and v the same, but now we add a small amount of kinetic friction to the ramp surface, how does the height h change as θ increases?"

This time, some of the kinetic energy is converted into work done by friction.

½ mv² = Fd + mgh

½ mv² = Fh / sin θ + mgh

The friction force can be found by drawing a free body diagram of the block.  There are three forces acting on the block.  Normal force perpendicular to the ramp, weight force pulling down, and friction force pushing down the ramp.

Sum of the forces perpendicular to the ramp:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Friction is normal force times coefficient of friction:

F = Nμ

F = mgμ cos θ

Substituting:

½ mv² = (mgμ cos θ) h / sin θ + mgh

½ mv² = mgμ h / tan θ + mgh

½ v² = gμ h / tan θ + gh

½ v² = (gμ / tan θ + g) h

As θ increases, tan θ increases.  That makes gμ / tan θ + g decrease.  Since v is constant, h must increase.

6 0
2 years ago
Read 2 more answers
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