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Nastasia [14]
3 years ago
7

For problems 6-9, using the formula net Force = Mass• Acceleration calculate the net force on the object.

Physics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

Find answers below

Explanation:

Mathematically, force is given by the formula;

Force = mass * acceleration

Given the following data;

6. Mass = 8 kg

Acceleration = 2 m/s²

Force = 8 * 2

Force = 16 Newton

7. Mass = 5 kg

Acceleration = 2 m/s²

Force = 5 * 2

Force = 10 Newton

8. Mass = 8 kg

Acceleration = 8 m/s²

Force = 8 * 8

Force = 64 Newton

9. Mass = 200 kg

Acceleration = 3 m/s²

Force = 200 * 3

Force = 600 Newton

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Answer:

25 m/s

Explanation:

This question can be solved using equation of motion

v^2 = u^2 + 2as

where

v is the final velocity

u is the initial velocity

s is the distance covered while moving from initial to final velocity

a is the acceleration

_____________________________________________

Given

box moved for distance of 62.5 m

Friction slows the box at –5.0 m/s2----> this statement means that there is deceleration , speed of truck decreases by 5 m/s in every second until the box comes to rest. Friction causes this deceleration.

thus in this problem

a = -5.0 m/s2

V = 0   as body came to rest due to friction deceleration

u the initial velocity we have to find

the initial velocity of box will be the same as speed of truck, as the box was in the truck and hence box will pick the speed of truck.

so if we find speed of box, we will be able get sped of truck as well.

using equation of motion

v^2 = u^2 + 2as\\0^2 = u^2 + 2*-5* 62.5\\0 = u^2 - 625\\u^2 = 625\\\sqrt{u^2} = \sqrt{625} \\u = 25

Thus, initial speed with the truck was travelling was 25 m/s.

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3 years ago
A key falls from a bridge that is 32 m above the water. It falls directly into a model boat, moving with constant velocity, that
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Answer:

Speed of the boat, v = 4.31 m/s

Explanation:

Given that,

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The model boat is 11 m from the point of impact when the key was released, d = 11 m

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s=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

t=\sqrt{\dfrac{2s}{g}}

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v=\dfrac{d}{t}

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v = 4.31 m/s

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A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t
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Here we will the speed of seagull which is v = 9 m/s

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T = t_1 + t_2

T = 20 + 7.7 = 27.7 min

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T = \frac{6000}{9} + \frac{6000}{9}

T = 22.22 min

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