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3 years ago

A photon has a wavelength of 500nm what is the energy associated

1 answer:

8 0

Given: Plank's constant h = 6.626 x 10⁻³⁴ J.s

Speed of light c = 2.998 x 10⁸ m/s

Wavelength λ = 500 nm convert to meter = 5 x 10⁻⁷ m

Required: Energy E =?

Formula: E = hc/λ

E = (6.626 X 10⁻³⁴ J.s)(2.998 X 10⁸ m/s)/5 x 10⁻⁷ m

E = 3.97 X 10⁻¹⁹ J or in termS of electron volt

E = 2.48 eV

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Which one is true ?????

maria [59]

Answer:

b. horizontal distance/time graph

Explanation:

d is incorrect because object is moving at the same pace the entire time

7 0

2 years ago

What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s 2 ) towards the Eart

Wittaler [7]

Answer:

The centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ is $1.020x10^{-3}m/s^{2}$

Explanation:

The centripetal acceleration is defined as:

$a = \frac{v^{2}}{r}$ (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

$v = \frac{2 \pi r}{T}$ (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude $71.9^{\circ}$ . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

$\cos \theta = \frac{adjacent}{hypotenuse}$

$\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}}$ (3)

Where $r_{71.9^{\circ}}$ is the radius at the latitude of $71.9^{\circ}$ and $r_{e}$ is the radius at the equator ( $6.37x10^{6}m$ ).

$r_{71.9^{\circ}}$ can be isolated from equation 3:

$r_{71.9^{\circ}} = r_{e} \cos \theta$ (4)

$r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})$

$r_{71.9^{\circ}} = 1.97x10^{6} m$

Then, equation 2 can be used

$v = \frac{2 \pi (1.97x10^{6} m)}{24h}$

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

$T = 24h . \frac{3600s}{1h}$ ⇒ $84600s$

$v = \frac{2 \pi (1.97x10^{6} m)}{84600s}$

$v = 146.31m/s$

Finally, equation 1 can be used:

$a = \frac{(146.31m/s)^{2}}{(1.97x10^{6}m)}$

$a = 0.010m/s^{2}$

Hence, the centripetal acceleration is $0.010m/s^{2}$

To given the centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ it is gotten:

$\frac{0.010m/s^{2}}{9.8 m/s^{2}} = 1.020x10^{-3}m/s^{2}$

6 0

3 years ago

a quickly moving house cat has 10 j of kinetic energy at speed v. at what speed will the cat have 20 j of kinetic energy

Brums [2.3K]

Answer:

2.00v

Explanation:

3 0

3 years ago

Which statement best describes comparative and descriptive investigations? They both include a question, procedure and conclusio

9966 [12]

Answer:

Hello,

The answer would be the first choice, "They both include a question, procedure and conclusion."

8 0

3 years ago

Read 2 more answers

Suppose the wavelength of the light is 450 nm . how much farther is it from the dot on the screen in the center of fringe e to t

lbvjy [14]

Since you are looking at a right fringe, the answer is all the time a multiple of the wavelength for the reason that the light makes constructive intrusion. If you are looking at the center (zeroth) fringe, the difference is (450)(0) = 0. For the first maximum, the difference is 450 nm. For the second, it is 450 x 2 = 900 nm. Basically, for the nth maxima, the difference is 450n.

8 0

3 years ago