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Answer:
T₂ = 43.46 °C
Explanation:
Given that:
The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)
It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J
Heat gain by water = Heat lost by the reaction
Thus,
For water:
Mass of water = 5100 g
Specific heat of water = 4.18 J/g°C
T₁ = 25 °C
T₂ = ?
Q = 393500 J
So,
T₂ = 43.46 °C
Answer : The mass of sodium carbonate added to neutralize must be,
Explanation :
First we have to calculate the moles of .
Given:
Molar mass of = 98 g/mole
Mass of =
Conversion used : (1 kg = 1000 g)
Now put all the given values in the above expression, we get:
The moles of is,
Now we have to calculate the moles of
The balanced neutralization reaction is:
From the balanced chemical reaction we conclude that,
As, 1 mole of neutralizes 1 mole of
So, of
neutralizes
Now we have to calculate the mass of
Molar mass of = 106 g/mole
Thus, the mass of sodium carbonate added to neutralize must be,