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1 year ago

A 46.2 L sample of gas exerts 237.4 mm Hg pressure at 139.2 ºC. What volume does the gas have at 702.4 mm Hg and 63.4 ºC?

Chemistry

1 answer:

zvonat [6]1 year ago

5 0

7.111 L is the volume of gas with 702.4 mm Hg and 63.4 ºC.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

$V_1=46.2 L$

$P_1=237.4 mm Hg$

$T_1=139.2 ºC$

$V_2=?$

$P_2=702.4 mm Hg$

$T_2=63.4 ºC$

Using the given below formula:

$\frac{V_1 X P_1}{T_1} = \frac{V_1 X P_1}{T_2}$

$\frac{46.2 L X 237.4 \;mm Hg}{139.2} = \frac{V_2 X 702.4 mm Hg}{63.4 ºC}$

$V_2$ = 7.111 L

Hence, 7.111 L is the volume of gas with 702.4 mm Hg and 63.4 ºC.

Learn more about the ideal gas here:

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