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2 years ago

What is the ion symbol for Lithium?

Chemistry

1 answer:

Bond [772]2 years ago

6 0

Answer:

Lithium is an alkali metal. The symbol for lithium element is ‘Li’. It belongs to group 1 of periodic table. Its electronic configuration is 1s2 2s1. It has one valence electron. So it loses one electron to attain stable configuration. Hence the symbol for lithium ion is ‘Li+’.

Explanation:

ithium is a chemical element with the symbol Li and atomic number 3. It is a soft, silvery-white alkali metal. Under standard conditions, it is the lightest metal and the lightest solid element. Like all alkali metals, lithium is highly reactive and flammable, and must be stored in mineral oil. When cut, it exhibits a metallic luster, but moist air corrodes it quickly to a dull silvery gray, then black tarnish. It never occurs freely in nature, but only in compounds, such as pegmatitic minerals, which were once the main source of lithium. Due to its solubility as an ion, it is present in ocean water and is commonly obtained from brines. Lithium metal is isolated electrolytically from a mixture of lithium chloride and potassium chloride.

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I need help solving this for chemistry. Don’t know where to start:/

Juli2301 [7.4K]

1 electron has charge =1.602* 10⁻¹⁹ C
1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol

One ion Co²⁺ takes 2e⁻ to become Co⁰.
1 mol of Co²⁺ ions take 2 mole of e⁻ to become Co⁰, so
0.30 mol Co²⁺ ions take mole of 0.60 mol e⁻ to become Co⁰

9.64*10⁴(C/1mol) *0.60 (mol)≈ 5.8 *10⁴ Coulombs.
Correct answer is C

8 0

3 years ago

In Lab 10 you make a stock solution of salicylic acid, and then four dilutions. The stock solution is made by diluting 5.00 ml o

Zigmanuir [339]

Answer:

Stock solution = 1.25 *10^-3 M

Dilution 1 = 5*10^-4 M

Dilution 2= 3.75 * 10^-4 M

Dilution 3 = 2.5 *10^-4 M

Dilution 4 = 1.25 *10^-4 M

Explanation:

Step 1: Data given

The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.

Step 2: Calculate the concentration of the stock solution:

M1*V1 = M2*V2

⇒ with M1 = the initial concentration = 1.250 *10^-2 M

⇒ with V1 = 5 mL = 5*10^-3 L

⇒ with M2 = TO BE DETERMINED

⇒ with V2 = 50 mL = 50 *10^-3 L

M2 = (M1*V1)/V2

M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3

M2 = 0.00125 M = 1.25 *10^-3 M

Step 3: Calculate dilution 1

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)

M2 = 0.0005 M = 5*10^-4 M

Step 4: Calculate dilution 2

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)

M2 = 0.000375 M = 3.75 * 10^-4 M

Step 5: Calculate dilution 3

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)

M2 = 0.00025 M = 2.5 *10^-4 M

Step 6: Calculate dilution 4

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)

M2 = 0.000125 M = 1.25 *10^-4 M

5 0

3 years ago

Which of the following is an SI base unit for measuring length?

Nikolay [14]

An SI base unit for measuring length would be meters.

5 0

3 years ago

I need help..would it be A???

Dovator [93]

Answer:

probably

Explanation:

Because fossil fuel is the main fuel source, so any fuels that are not fossil fuels are alternative.

7 0

3 years ago

Calculate the nuclear binding energy in mega-electronvolts (MeV) per nucleon for 136 Ba . 136 Ba has a nuclear mass of 135.905 a

sergey [27]

Answer:

8.194 Mev per nucleon

Explanation:

Mass of Barium = 135.905 amu

number of proton = 56, number of neutron = 80

Md = (Mp + Mn) - Mb Mp is the mass of proton, Mn is the mass of neutron, Mb is the mass of barium and Md is the mass defect

Mn = 1.00867 amu Mp = 1.00728 amu

Md = ( 56 ( 1.00728) + 80 ( 1.00867) = 137.1013 - 135.905 =1.1963 amu

Md = 1.1963 × 1 ÷ ( 6.02214 × 10 ²⁶ amu ) = 1.9865 × 10 ⁻²⁷ kg

Energy = mc² = 1.9865 × 10 ⁻²⁷ kg × (2.99792 × 10 ⁸ m/s)²

E= 1.78537 × 10⁻¹⁰ J

to convert to Mev

1.78537 × 10⁻¹⁰ × 6241457006000 = 1114.33 Mev

binding energy per nucleon = 1114.33 / 136 =8.194 Mev per nucleon

5 0

3 years ago