Correction: The temperature change is from 20 °C to 30 °C.
Answer:
Cp = 1.0032 J.g⁻¹.°C⁻¹
Solution:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 5016 J
m = mass = 500 g
Cp = Specific Heat Capacity = ??
ΔT = Change in Temperature = 30 °C - 20 °C = 10 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 5016 J / (500 g × 10 °C)
Cp = 1.0032 J.g⁻¹.°C⁻¹
The mass would still be the same 25.0 g but the volume would be bigger
Answer:
0.027 M HCl
Explanation:
The chemical equation of the neutralization is:
1 NaOH + 1 HCl -> 1 H2O + 1 NaCl
Because the ratio of NaOH and HCl is 1:1 you can use the M1V1=M2V2 formula.
(75 mL)(0.5 M NaOH) = (165 mL)(M HCl)
It requires 0.027 M HCl.
The correct answer is option A. Energy cannot be created during an ordinary chemical reaction. There is no such thing as an ordinary chemical reaction. Energy cannot be created or destroyed this is according to the law of conservation of energy. It can only be transformed from one form to another form.
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