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Luden [163]
2 years ago
6

What can we use to help us predict the results of reaction when we put metals into competition?

Chemistry
1 answer:
Effectus [21]2 years ago
7 0

The activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.

<h3>What is used in comparing reactivity of metals?</h3>

The reactivity of metals can be compared using their electrode potentials which is a measures of the ability of the metal to donate electrons to another metal.

When comparing the reactivity of metals, the metal with the lesser negative electrode potential will be more reactive than another with a greater negative or positive electrode potential.

Therefore, the activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.

Learn more about activity series of metals at: brainly.com/question/17469010

#SPJ12

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The elements on the Periodic Table are arranged in order of increasing
Nookie1986 [14]
<span>The elements on the Periodic Table are arranged in order of increasing "Atomic number"

In short, Your Answer would be Option B

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6 0
4 years ago
For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
3 years ago
2 drops of vinegar &amp; 2 drops ammonia solution or not​
Naya [18.7K]

Answer:

No, this is false because we know about the law that says if you add two things together you are adding the masses together, 2 drops of vinegar and 2 drops of ammonia would equal four drops of solution not two

Hope this helps!!

Explanation:

5 0
3 years ago
Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

6 0
4 years ago
Electrons are:
Svetllana [295]

Answer:

B. Are fixed within electron orbitals

Explanation:

Electrons are found in the energy levels

4 0
3 years ago
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