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Luden [163]
2 years ago
6

What can we use to help us predict the results of reaction when we put metals into competition?

Chemistry
1 answer:
Effectus [21]2 years ago
7 0

The activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.

<h3>What is used in comparing reactivity of metals?</h3>

The reactivity of metals can be compared using their electrode potentials which is a measures of the ability of the metal to donate electrons to another metal.

When comparing the reactivity of metals, the metal with the lesser negative electrode potential will be more reactive than another with a greater negative or positive electrode potential.

Therefore, the activity series of metals as well as the electrode potential of metals can be used to compare the reactivity of metals.

Learn more about activity series of metals at: brainly.com/question/17469010

#SPJ12

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MnS+HCl H 2 S+MnCl 2 Which set of coefficients would balance the equation?
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Answer:

1,2,1,1

Explanation:

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3 years ago
How many moles are in 9.12 x 1023 molecules of sugar?​
aleksandrvk [35]

Answer:

1.514 moles

Explanation:

For this problem you want to use dimensional analysis and cancel out your molecules of sugar and be left with moles of sugar. We know that 1 mole (of anything) = 6.022 x 10 ^ 23 molecules, so we should use that conversion to help us. Start with 9.12 x 10 ^23 molecules and divide by 6.022 x 10 ^ 23 molecules, and you will be left with moles.

Hope this helps!

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2 years ago
How does the chemical formula for the nitrite ion differ from the chemical formula for the nitrate ion?
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8 0
3 years ago
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Convert 3 mol of Co, to grams.
GuDViN [60]

Answer:

176.7996 grams

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3 0
3 years ago
In the laboratory you are asked to make a 0.565 m sodium bromide solution using 315 grams of water. How many grams of sodium bro
Scorpion4ik [409]

Answer : The mass of sodium bromide added should be, 18.3 grams.

Explanation :

Molality : It is defined as the number of moles of solute present in kilograms of solvent.

Formula used :

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}

Solute is, NaBr and solvent is, water.

Given:

Molality of NaBr = 0.565 mol/kg

Molar mass of NaBr = 103 g/mole

Mass of water = 315 g

Now put all the given values in the above formula, we get:

0.565mol/kg=\frac{\text{Mass of NaBr}\times 1000}{103g/mole\times 315g}

\text{Mass of NaBr}=18.3g

Thus, the mass of sodium bromide added should be, 18.3 grams.

6 0
3 years ago
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