If there are 0.2 M solutions of both acid and base, the concentrations of hydrogen and hydroxide ions will be equal at equivalence point.
The reaction of sulfuric acid and a basic solution BOH occurs as follows;
H2SO4(aq) + 2BOH(aq) -----> B2SO4(aq) + 2H2O(l)
In the question, we are told that that both the solution of the sulfuric acid and the basic solution are 0.2 M.
The point where all the hydrogen and hydroxide ions have reacted according to the stoichiometry of the reaction. If there is really equimolar amounts of acid and base, the concentration of hydrogen and hydroxide ions will be equal at equivalence point.
Learn more: brainly.com/question/2192784
Answer: D- making flexible eyeglass frames
Explanation: my powerful mind
2AgNO3 + Ni2+ = Ni(NO3)2 + 2Ag<span>+</span>
From the reaction,
it can be seen that AgNO3 and Ni2+ has following amount of substance
relationshep:
n(AgNO3):n(Ni)=2:1
From the relationshep we can determinate requred moles of Ni2+:
n(AgNO3)=m/M= 15.5/169.87=0.09 moles
So, n (Ni)=n(AgNO3)/2=0.045 moles
Finaly needed mass of Ni2+ is:
m(Ni2+)=nxM=0,045x58.7=2.64g
Answer:
The reasons why the seemingly floating bubbles disappear was that they tend to loss their latent heat to the water molecules at the surface water.
Explanation:
Heat energy has a considerable effect on the velocity of molecules including water. The water molecules below the container will receive much more heat energy than those above it. This heat energy in the form of specific heat capacity and latent heat that result in the increase in the speed of individual molecules of water and finally to the escape of the molecules to a colder region of the container, in this case the upper region. At the collision of the bottom water to the surface water, they tend to exchange their heat content, the hotter molecules will lose their heat to the cold ones. When the formerly hot molecules encounter this, it will result in lowering the temperature and consequentially to the reduction of their movement, once in the form of bubble, now become ordinary water. This convectional transfer of heat energy will continue until the whole system has a uniform temperature depending on the consistency of the heat source.
