Question

2 large parallel plates are 2.0 cm apart. the strength of the electric plates between them is 100.0 n/c . what is the difference in the voltage between them?

Answer 1

Hello!

We can use the following equation for the potential difference between two parallel plates given an electric field and separation distance:
$V = Ed$

V = Potential Difference (? V)
E = Electric field strength (100.0 N/C)

d = distance between places (0.02 m)

Plug in the values and solve.

$V = (100)(0.02) = \boxed{2 V}$