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d1i1m1o1n [39]
3 years ago
10

Two children playing on a frictionless garden gate invent a new game called "gate". The idea is that they will get on opposite s

ides of the gate and each push such that the gate does not move. If they both push horizontally and perpendicular to the gate and one child pushes with a force of 170 N at a distance of 0.590 m from the hinges, determine the force the second child must exert in order to keep the gate from moving if she pushes at a distance of 0.430 m from the hinges.
Physics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

  • <u>233 N</u>

Explanation:

The balance condition, to keep the gate from moving, requires that the net torque be zero, this is, the torques on both sides of the gate must be equal.

  • Torque equation: τ = F × d

a) <u>Torque applied by one of the children:</u>

  • F = 170 N
  • d = 0.590 m

  • τ₁ = 170 N × 0.590 m

b) <u>Torque applied by the second child</u>:

  • F = ?
  • d = 0.430 m

  • τ₂ = F × 0.590 m

c) <u>Equilibrium condition</u>:

  • τ₁ = τ₂
  • 170 N × 0.590m = F × 0.430m

  • F = 170 N × 0.590 m / 0.430 m = 233 N ← answer
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A runner runs 10 miles in 1 hour. how far could they run in 2 hours in m/s?
stiv31 [10]

Answer:

4.47 m/s.

Explanation:

distance traveled, d = 10 miles

time, t = 1 hour

Speed of the runner, v = d / t

Speed of the runner = 10 miles / 1

Speed of the runner = 10 mph

1 mph ----------------------- 0.44704 m/s

10 mph -----------------------?

= 4.47 m/s

Thus, in 2 hours the distance traveled will change but the speed it still 10 mph or 4.47 m/s.

3 0
3 years ago
How many kcalories are provided by a food that contains 25 g carbohydrate, 6 g protein, and 5 g fat?
MrRissso [65]

<u>169 Kcalories</u> are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.

Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.

Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.

Simply put it, take note of the following conversions:

  • 1 gram of carbohydrate is 4kcal
  • 1 gram of protein is also 4kcal
  • Though, 1 gram of fat is 9kcal

So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.

1.    25g x 4kcal/g = 100kcal

2.    6g x 4kcal/g = 24kcal

3.    5g x 9kcal/g = 45kcal

4.    100kcal + 24kcal + 45kcal = 169kcal!


Therefore, the food contains 169 kilo-calories!

You might be interested in nutrient density of an orange juice per kcalorie. Look here: brainly.com/question/26495283

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7 0
2 years ago
What is the internal energy of 2.00 mol of diatomic hydrogen gas (H2) at 35°C?
djyliett [7]
As you mentioned, we will use <span>Equipartition Theorem.
</span><span>H2 has 5 degrees of freedom; 3 translations and 2 rotation
</span>Therefore:
Internal energy = (5/2) nRT
You just substitute in the equation with the values of R and T and calculate the internal energy as follows:
Internal energy = (5/2) x 2 x <span>8.314 x 308 = 32.0089 x 10^3 J</span>
4 0
2 years ago
Why polarization does not occur in dry cell?​
Arisa [49]

Answer:

Manganese oxide prevents polarisation in dry cells. - Polarization is a defect that occurs in simple electric cells due to the accumulation of hydrogen gas around the positive electrode. ... - MnO2 reacts with H2 and forms water as byproduct, so depolarization doesn't occur.

7 0
3 years ago
Marcia flew her ultralight plane to a nearby town against a head wind of 15 km/h in 2h 20 min. the return trip under the same wi
insens350 [35]

Let the distance between the towns be d and the speed of the air be s.

distance = speed * time

convert the minutes time into hours.

When flying into the wind, ground speed will be air speed MINUS wind speed, hence the against the wind trip is described by:

d

s−15

=

7

3

return trip is then :

d

s+15

=

7

5

Cross-multiplying both we get the two-variable system:

3d=7∗(s−15)5d=7∗(s+15)

3d=7s−1055d=7s+105

subtract first equation from second equation we get

2d=210d=105km

Substitute the value of d in the above equations for s.

5∗105=7s+1057s=420s=60km/hr

8 0
3 years ago
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