Answer : The value of the constant for a second order reaction is, 
Explanation :
The expression used for second order kinetics is:
![kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}](https://tex.z-dn.net/?f=kt%3D%5Cfrac%7B1%7D%7B%5BA_t%5D%7D-%5Cfrac%7B1%7D%7B%5BA_o%5D%7D)
where,
k = rate constant = ?
t = time = 17s
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D) = final concentration = 0.0981 M
 = final concentration = 0.0981 M
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D) = initial concentration = 0.657 M
 = initial concentration = 0.657 M
Now put all the given values in the above expression, we get:


Therefore, the value of the constant for a second order reaction is, 
 
        
             
        
        
        
Atomic number is equal to the number of protons and electrons
Atomic mass - protons = neutrons
protons + neutrons = atomic mass
I hope this helps
        
             
        
        
        
Answer:
Explanation:
We know that , If the frictional force on a system is zero , then the total energy of a system will be conserved.
By using energy conservation
KE₁ +  U₁ = KE₂ + U₂
KE₁=Kinetic energy at location 1
 U₁ =Potential energy at location 1
KE₂=Kinetic energy at location 2
U₂=Potential energy at location 2
Therefore, Raymond is thinking in a right way.
 
        
             
        
        
        
Answer:
230 N
Explanation:
At the lowest position , the velocity is maximum hence at this point, maximum support force  T  is given by the branch.
The swinging motion of the ape on a vertical circular path , will require
a centripetal force  in upward direction . This is related to weight as follows
T - mg = m v² / R
R is radius of circular path . m is mass of the ape and velocity is 3.2 m/s
T =  mg -  mv² / R
T = 8.5 X 9.8 + 8.5 X 3.2² / .60  { R is length of hand of ape. }
T = 83.3 + 145.06
= 228.36
= 230 N ( approximately )
 
        
             
        
        
        
Answer: a) 12857.1 m/s/s b) 578.6 N
Explanation:
Impulse = change in momentum
Ft = mV2 - mV1
V = AT, 45 / .0035 = 12857.1 m/s/s
(b) .045 x 12857.1 = 578.6 N