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Vera_Pavlovna [14]
3 years ago
15

You pull the plunger back on a pinball machine. The spring is pulled back 25 cm from its rest position and has a spring constant

of 78 N/m. What speed will a 50.0 g ball in front of the spring reach when the spring has returned to its rest position?
Physics
1 answer:
NemiM [27]3 years ago
5 0

Answer:

9.9 m/s

Explanation:

from the question we are given the following

length (L) = 25cm = 25 / 100 = 0.25m

spring constant (K) = 78 N/m

mass of the ball (m) = 50g = 50 / 1000 = 0.05 kg

At maximum compression all energy is potential energy and at maximum velocity all energy is kinetic energy, and from the conservation of energy the two energy must be he same. Therefore

potential energy at max compression = kinetic energy at max velocity

(1/2) x K x L^2 = (1/2) x m x V^2

(1/2) x 78 x 0.25^2 = (1/2) x 0.05 x V^2

V^2 = 97.6

V =  9.9 m/s

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The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proto
igor_vitrenko [27]

a) The angular velocity of the electron is 4.12\cdot 10^{16} rad/s

b) The number of revolutions per second is 6.54\cdot 10^{15} rev/s

c) The centripetal acceleration of the electron is 8.98\cdot 10^{22} m/s^2

Explanation:

a)

This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.

The angular velocity of an object in uniform circular motion is given by

\omega = \frac{v}{r}

where

v is the linear speed

r is the radius of the trajectory

For the electron orbiting around the proton, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

Therefore, the angular velocity is

\omega=\frac{2.18\cdot 10^6}{5.29\cdot 10^{-11}}=4.12\cdot 10^{16} rad/s

b)

The period of revolution of the electron is given by

T=\frac{2\pi}{\omega}

where

\omega = 4.12\cdot 10^{16}rad/s is the angular velocity

Substituting,

T=\frac{2\pi}{4.12\cdot 10^{16}}=1.53\cdot 10^{-16}s

The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:

f=\frac{1}{T}=\frac{1}{1.53\cdot 10^{-16}}=6.54\cdot 10^{15} rev/s

c)

The centripetal acceleration of an object in circular motion is

a=\frac{v^2}{r}

where

v is the linear speed

r is the radius of the circle

For the electron, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

Therefore, the centripetal acceleration is

a=\frac{(2.18\cdot 10^6)^2}{5.29\cdot 10^{-11}}=8.98\cdot 10^{22} m/s^2

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

7 0
4 years ago
A 3.0 kg ball is lifted two meters upward in two seconds, and a 6.0 kg ball is lifted one meter upward in one second? Which requ
Sav [38]

Answer:

1. They both uses same energy

2. The 6 kg ball requires more power than 3kg ball

Explanation:

Sample 1

m = 3kg

g= 10m/s^2

h = 2m

t = 2secs

W = mgh = 3 x 10 x 2 = 60J

P= w/t = 60/2 = 30watts

Sample 2

m = 6kg

g= 10m/s^2

h = 1m

t = 1sec

W = mgh = 6 x 10 x 1 = 60J

P= w/t = 60/1 = 60watts

They both uses same energy but different power. The 6 kg ball requires more power than 3kg ball

3 0
4 years ago
Convert 1.5 radian into milliradians.
Alex

Answer:

1500 milliradians

Explanation:

Data provided in the question:

1.5 radians

Now,

1 radians consists of  1000 milliradians

1 milli = 1000

thus for the 1.5 radians, we have

1.5 radians = 1.5 multiplied by 1000 milliradians

or

1.5 radians = 1500 milliradians

Hence, after the conversion

1.5 radians equals to the value 1500 milliradians

4 0
3 years ago
Come up with an example of classical conditioning in your own life or in the real world. Be sure to identify the unconditioned s
mote1985 [20]

Answer:   All learning occurs through interactions with the environment; The environment ... In the before conditioning phase, an unconditioned stimulus is paired with an ... In our example, the conditioned response would be feeling hungry when you heard ... reinforce the salivation response to make sure the behavior is well learned.

4 0
3 years ago
Water thtat is returned to the environment after secondary treatment is known as _____.
Margarita [4]

The answer is C) Effluent

4 0
4 years ago
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