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kobusy [5.1K]
3 years ago
12

Which of these scientists had the greatest contribution to early microscopy?

Physics
1 answer:
Alisiya [41]3 years ago
5 0
B. I think is the correct answer
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Why do you suppose the stomach contains acid? what do you think happens when there is more acid than food in the stomach?
jeka94

Answer:

Your stomach acid helps you break down and digest your food. Sometimes, a higher than normal amount of stomach acid can be produced. This can lead to symptoms like abdominal pain, nausea, bloating, and heartburn.

Explanation:

brainliest plz

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3 years ago
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A car is traveling north at 17.7m/s After 12 s its velocity is 14.1m/s in the same direction. Find the magnitude and direction o
dem82 [27]

Answer:

Option B

0.3 m/s2 South

Explanation:

Acceleration, a=\frac {v-u}{t} where v and u are final and initial velocities respectively, t is the time taken

Substituting 14.1 m/s for v, 17.7 m/s for u and 12 s for t then

a=\frac {14.1 m/s- 17.7 m/s}{12}=-0.3 m/s^{2}

Since this is negative acceleration, it's direction is opposite hence 0.3 m/s2 South

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3 years ago
Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
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Answer:

1.45544 J

Explanation:

See attachment

5 0
3 years ago
(a) A certain parallel-plate capacitor has plates of area 4.00m2 , separated by 0.0100 mm of nylon, and stores 0.170 C of charge
lilavasa [31]

The applied voltage is 1.41* 10⁴ kV.

Calculation of applied voltage-

The capacitance of parallel plates in the absence of a dielectric is:

C = ∈₀A/d

where, "d" = the spacing between the plates = 0.01 * 10⁻³ m

"A" = the area of the plates = 4 m²

"∈₀" = the constant = 8.85419*10⁻¹² C²/Nm²

So, C₀ = \frac{8.85419*10^{-12}*4 }{0.0100*10^{-3} }

          = 3541.67 *10⁻⁹ F

The dielectric constant, κ= 3.4, is defined as:

κ = C/C₀

The effective capacitance (with the dielectric) is denoted by "C", whereas the original capacitance is denoted by "C₀". (without the dielectric).

As a result, the new capacitance is:

C = κC₀

However, capacitance is connected to a voltage by:

C = Q/V

utilizing the increased capacitance and accounting for "V":

κC₀ = Q/V

V = Q/κC₀ = \frac{0.170}{3.4 * 3541.67 *10^{-9}  } = 1.41* 10⁴ kV

Therefore the applied voltage is 1.41* 10⁴ kV.

Learn more about the capacitance here:

brainly.com/question/14762323

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8 0
2 years ago
E. A driver speeds up his vehicle while moving up a hill.<br>Why?​
sashaice [31]

Answer:

When we go go up a hill,we will be going against the gravitational force. So we experience a gravitational pull towards the ground. So it is necessary to speed up the car while moving up hill.

Explanation:

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