Force = (mass) x (acceleration)
Mass = (force) / (acceleration)
There was 150N of force in one direction and 100N of 'force' in
the other direction. The net force on the object was (150 - 100) = 50N .
Acceleration = (change in speed) / (time for the change)
= (10 m/s) / (5s) = 2 m/s²
Mass = (net force) / (acceleration) = (50 N) / (2 m/s²) = 25 kilograms
Answer:
V = 6 m/s
Explanation:
Given that,
Initial speed of an object is 20 m/s
Final speed of an object is 10 m/s
Time, t = 5 s
We need to find the average speed of the object during these 5 seconds. Let it is equal to V. Here, time is same. The average speed is given by :

So, the average speed of the object is 6 m/s.
Answer:

Explanation:
Kinetic energy can be found using the following formula.

where <em>m</em> is the mass and <em>v</em> is the velocity.
The mass of the toy plane is 20 kilograms and the velocity is 10 meters per second.

Substitute the values into the formula.

Solve the exponent first.
- (10 m/s)²= 10 m/s *10 m/s= 100 m²/s²

Multiply the last two numbers together.

Multiply by 1/2 or divide by 2.

- 1 kilogram square meter per square second is equal to 1 Joule.
- Our answer of 1000 kg*m²/s² is equal to 1000 Joules

The kinetic energy of the toy plane is <u>1000 Joules</u>
<h2>Potential energy lost by 10 N rock will be greater</h2>
Explanation:
Two rocks of 5N and 10N falls from the same height . Thus they will loose the potential energy.
The potential energy lost = mass x acceleration due to gravity x height
The potential energy lost by first 5 N rock = 5 h
Because weight of rock m g = 5 N
Similarly , the potential energy lost by 10 N Rock = 10 h
here weight of rock m g = 10 N
Thus comparing these two , the potential energy lost by 10 N rock is greater than that of 5 N rock .
Force applied on the car due to engine is given as
towards right
Also there is a force on the car towards left due to air drag
towards left
now the net force on the car will be given as

now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.
So we can say



So here net force on the car will be 150 N towards right and hence it will accelerate due to same force.