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3 years ago

What is an odometer?

Physics

2 answers:

ra1l [238]3 years ago

6 0

Answer:

It is a instrument used to measure the distance traveled by a vehicle.

Explanation:

This is what it looks like ↓

Oksana_A [137]3 years ago

5 0

Answer:

Odometer is the device that measures and shows the distance a vehicle have travelled.

Hope this help you :3

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True. These are the characteristics of a social drinker.

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3 years ago

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GenaCL600 [577]

D. 65.1 is the answer

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3 years ago

Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p

Marta_Voda [28]

Answer:

Acceleration, $a=9.91\times 10^{15}\ m/s^2$

Explanation:

It is given that,

Separation between the protons, $r=3.73\ nm=3.73\times 10^{-9}\ m$

Charge on protons, $q=1.6\times 10^{-19}\ C$

Mass of protons, $m=1.67\times 10^{-27}\ kg$

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

$ma=\dfrac{kq^2}{r^2}$

$a=\dfrac{kq^2}{mr^2}$

$a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}$

$a=9.91\times 10^{15}\ m/s^2$

So, the acceleration of two isolated protons is $9.91\times 10^{15}\ m/s^2$ . Hence, this is the required solution.

3 0

2 years ago

A sphere of radius R contains charge Q spread uniformly throughout its volume. Find an expression for the electrostatic energy c

tensa zangetsu [6.8K]

Answer:

$E = \frac{3kQ^2}{5R}$

Explanation:

Let the sphere is uniformly charge to radius "r" and due to this charged sphere the electric potential on its surface is given as

$V = \frac{kq}{r}$

now we can say that

$q = \frac{Q}{\frac{4}{3}\pi R^3} (\frac{4}{3}\pi r^3)$

$q = \frac{Qr^3}{R^3}$

now electric potential is given as

$V = \frac{k\frac{Qr^3}{R^3}}{r}$

$V = \frac{kQr^2}{R^3}$

now work done to bring a small charge from infinite to the surface of this sphere is given as

$dW = V dq$

$dW = \frac{kQr^2}{R^3} dq$

here we know that

$dq = \frac{3Qr^2dr}{R^3}$

now the total energy of the sphere is given as

$E = \int dW$

$E = \int_0^R \frac{kQr^2}{R^3} (\frac{3Qr^2dr}{R^3})$

$E = \frac{3kQ^2}{R^6} (\frac{R^5}{5} - 0)$

$E = \frac{3kQ^2}{5R}$

7 0

3 years ago

Un tubo metálico tiene 100 metros de longitud cuando está a 0 oC y 100,13 metros cuando se calienta hasta 100 oC. ¿Cuál es el co

Artyom0805 [142]

Answer:

α= 1.3 10-5 ºC⁻¹

Explanation:

La dilatación termica de los cuerpos esta dada por la relación

ΔL = L₀ α ( T -T₀)

en este caso nos piden el coeficiente de dilatación térmica

α =DL/L₀ DT

calculemos

α = ( 100,13 -100)/[100 (100 – 0)]

α = 1,3 10-5 ºC⁻¹

Traduction

The thermal expansion of bodies is given by the relationship

ΔL = L₀ α (T -T₀)

in this case they ask us for the coefficient of thermal expansion

α = ΔL / L₀ ΔT

let's calculate

α = (100,13 -100) / [100 (100 - 0)]

α= 1.3 10-5 ºC⁻¹

6 0

3 years ago