Answer:



Explanation:
Molar mass of NaCl = 58.44 g/mol
Mass of NaCl = 195 g
Volume of solution = 4.05 L
Molarity of solution is

The molarity of the solution is 
Moles of NaCl = 4.63 mol
Volume is given by

The volume of the solution that contains the required amount NaCl is 
Volume of solution = 
Moles of solution is given by

The number of moles of NaCl is
.
The empirical formula of this compound is 
<u>Given the following data:</u>
<u>Scientific data:</u>
- Molar mass of hydrogen (H) = 1.0 g/mol.
- Molar mass of sulfur (S) = 32 g/mol.
- Molar mass of oxygen (O) = 16 g/mol.
To determine the empirical formula of this compound:
Note: We would assume that the mass of the compound is 100 grams.
Hence, the mass of its constituent elements are:
- Mass of hydrogen (H) = 2.00 grams
- Mass of sulfur (S) = 32.7 grams
- Mass of oxygen (O) = 65.3 grams
Next, we would determine the number of moles of each element by using this formula:

<u>For </u><u>hydrogen</u><u> (</u><u>H</u><u>):</u>

Number of moles = 2.0 moles
<u>For </u><u>sulfur</u><u> (</u><u>S</u><u>):</u>

Number of moles = 1.0 moles
<u>For </u><u>oxygen</u><u> (</u><u>O</u><u>):</u>

Number of moles = 4.0 moles
Empirical formula = 
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Answer:
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Explanation: