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Amanda [17]
2 years ago
8

If a 10.0ml sample of unknown liquid has a mass of 7.553g what is the density of the unknown liquid

Chemistry
1 answer:
Burka [1]2 years ago
6 0

The density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml

<h3>What is density?</h3>

Density is the measurement of how tightly a material is packed together.

Given data:

Weight =7.553g

Volume = 10.0ml

Density =\frac{mass}{volume}

Density =\frac{7.553g}{10.0ml}

Density = 0.7553 g/ml

Hence, the density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml.

Learn more about density here:

brainly.com/question/15164682

#SPJ1

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Luden [163]

Answer:

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8 0
3 years ago
Be sure to answer all parts. For an aqueous solution of sodium chloride (NaCl), determine the molarity of 4.05 L of a solution t
SpyIntel [72]

Answer:

0.824\ \text{M}

5.62\ \text{L}

20.89\ \text{mol}

Explanation:

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = 195 g

Volume of solution = 4.05 L

Molarity of solution is

\dfrac{195}{4.05}\times \dfrac{1}{58.44}=0.824\ \text{M}

The molarity of the solution is 0.824\ \text{M}

Moles of NaCl = 4.63 mol

Volume is given by

\dfrac{4.63}{0.824}=5.62\ \text{L}

The volume of the solution that contains the required amount NaCl is 5.62\ \text{L}

Volume of solution = 25.35\ \text{L}

Moles of solution is given by

0.824\times 25.35=20.89\ \text{mol}

The number of moles of NaCl is 20.89\ \text{mol}.

6 0
3 years ago
A compound is 2. 00% H by mass, 32. 7% S by mass, and 65. 3% O by mass. What is its empirical formula? The final step is to use
LekaFEV [45]

The empirical formula of this compound is H_2SO_4

<u>Given the following data:</u>

  • Percentage of H = 2.00%
  • Percentage of S = 32.7%
  • Percentage of O = 65.3%

<u>Scientific data:</u>

  • Molar mass of hydrogen (H) = 1.0 g/mol.
  • Molar mass of sulfur (S) = 32 g/mol.
  • Molar mass of oxygen (O) = 16 g/mol.

To determine the empirical formula of this compound:

Note: We would assume that the mass of the compound is 100 grams.

Hence, the mass of its constituent elements are:

  • Mass of hydrogen (H) = 2.00 grams
  • Mass of sulfur (S) = 32.7 grams
  • Mass of oxygen (O) = 65.3 grams

Next, we would determine the number of moles of each element by using this formula:

Number\;of\;moles = \frac{mass}{molar\;mass}

<u>For </u><u>hydrogen</u><u> (</u><u>H</u><u>):</u>

Number\;of\;moles = \frac{2.00}{1}

Number of moles = 2.0 moles

<u>For </u><u>sulfur</u><u> (</u><u>S</u><u>):</u>

Number\;of\;moles = \frac{32.7}{32}

Number of moles = 1.0 moles

<u>For </u><u>oxygen</u><u> (</u><u>O</u><u>):</u>

Number\;of\;moles = \frac{65.3}{16}

Number of moles = 4.0 moles

Empirical formula = H_2SO_4

Read more: brainly.com/question/21280037

3 0
2 years ago
Question 10 of In which way does a balanced chemical equation demonstrate the conservation of matter? A. It shows the same numbe
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Answer:

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Explanation:

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Answer:

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Explanation:

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