Answer:
TiCl2
Explanation:
Mass of the chloride of titanium= 1.31 g
Mass of titanium= 0.528 g
Therefore mass of chlorine = 1.31-0.528 = 0.782 g
To determine the empirical formulae of the titanium chloride, divide the mass of each element by its relative atomic mass and divide through by the lowest ratio.
Ti- 0.528/48 = 0.011, Cl- 0.782/35.5 = 0.022
Ti- 0.011/0.011 , Cl- 0.022/0.011
Ti- 1, Cl-2
Hence the required empirical formula is TiCl2
Answer:
Explanation:
Firstly of all we have to construct the min-heap of the k-sub list and each sub list which is a node in the constructed min-heap.
We have several steps to follows:
Step-1. When we compare the two sub lists, at the starting we can compare their first elements which is actually their minimum elements.
Step-2. The min-heap formation will cost be O(k) time.
Step-3. After the step 1 & step 2 we can run the minimum algorithm which can be extracted from the minimum element in the root list.
Step-4. Then Update the root list in the heap and after that simplify the min-heap as maintained by the new minimum element in the root list.
Step-5. If any root sub-list becomes empty in the step 4 then we can take any leaf sub-list from the root and simplify it.
Step-6. At every Extraction of the element it can take up to O(log k) time.
Hence, We can say that the extract of n element in the total whose
Running time will be O(n log k + k) which can be equal to the O(n log k+ k) (since k < n).
False. Due to:
Entropy increases with molecular size (mass of compound)
HBr has greater molecular size (molar mass) than HCl
The value of standard entropy of HCl(g) is 187 joules/ kelvin
The value of standard entropy of HBr(g) is 199 joules / kelvin
Mass of the bullet (m) = 8.13 g = 0.00813 kg
velocity of the bullet (v) = 1337 miles/hr
The de Broglie wavelength (∧) of an object of mass (m) travelling at a velocity (v) is given as:
∧ = h/m*v
where h = Planck's constant = 6.626 *10^-34 kgm2/s
Convert velocity from miles/hr to m/s
1 mile/hr = 0.447 m/s
1337 miles/hr = 0.447*1337 = 597.64 m/s
∧ = 6.626*10^-34 m2.Kg.s-1/0.00813 kg * 597.64 ms-1
∧ = 1.363*10^-34 m
Density is given by the equation D=m/V, were D is density, m is mass in grams, and V is volume in cubic centimeters.
In this problem, we have density and we have mass so we can plug into the equation and solve for V.
38.6=270.2/V
<em>*Multiply both sides by V*</em>
38.6V=270.2
<em>*Divide both sides by 38.6*</em>
V=7
The volume of the gold nugget is 7cm3.
Hope this helps!!
