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Amanda [17]
2 years ago
8

If a 10.0ml sample of unknown liquid has a mass of 7.553g what is the density of the unknown liquid

Chemistry
1 answer:
Burka [1]2 years ago
6 0

The density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml

<h3>What is density?</h3>

Density is the measurement of how tightly a material is packed together.

Given data:

Weight =7.553g

Volume = 10.0ml

Density =\frac{mass}{volume}

Density =\frac{7.553g}{10.0ml}

Density = 0.7553 g/ml

Hence, the density of the unknown liquid has a mass of 7.553g is 0.7553 g/ml.

Learn more about density here:

brainly.com/question/15164682

#SPJ1

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How many moles of KCL is in a 3M solution of KCL
netineya [11]

Answer:

223.6539

Explanation:

1 mole is equal to 1 moles KCl, or 74.5513 grams

4 0
3 years ago
Consider a solution that is 1.3×10−2 M in Ba2+ and 2.0×10−2 M in Ca2+. Ksp(BaSO4)=1.07×10−10 Ksp(CaSO4)=7.10×10−5 If sodium sulf
skad [1K]

Answer:

Explanation:

Ksp(BaSO4)=1.07×10−10

BaSO₄ → Ba²⁺ + SO₄²⁻

1.07×10⁻¹⁰ = ( Ba²⁺) × ( SO₄²⁻)

but Ba²⁺ = 1.3×10⁻² M

1.07×10⁻¹⁰  = 1.3×10⁻² M × ( SO₄²⁻)

( SO₄²⁻)  = 1.07×10⁻¹⁰  / 1.3×10⁻² = 0.823 × 10⁻⁸ M

while Ksp(CaSO4)=7.10×10−5

CaSO₄ → Ca²⁺ + SO₄²⁻

7.10×10⁻⁵ = 2.0×10⁻² × ( SO₄²⁻)

( SO₄²⁻)  = 7.10×10⁻⁵  /  2.0×10⁻² = 3.55 × 10⁻³ M

comparing the concentration of sulfate ions, Ba²⁺ cation will precipitate first because the Ba²⁺ requires 0.823 × 10⁻⁸ M sodium sulfate which less compared the about needed by CaSO₄

7 0
3 years ago
Please help me the picture is above.
Andreas93 [3]

Answer:

A

Explanation:

bc inorganic compoud refers to all compound that do not contain carbons.

4 0
3 years ago
Which describes the elements in a given group of the periodic table?
victus00 [196]
C is the answer I think
3 0
3 years ago
How many grams of HNO3 are produced when 59.0 g of NO2 completely reacts?
Anettt [7]

Answer:

53.7 grams of HNO3 will be produced

Explanation:

Step 1: Data given

Mass of NO2 = 59.0 grams

Molar mass NO2 = 46.0 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 59.0 grams / 46.0 g/mol

Moles NO2 = 1.28 moles

Step 4: Calculate moles HNO3

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 1.28 moles NO2 we'll have 2/3 * 1.28 =0.853 moles HNO3

Step 7: Calculate mass HNO3

Mass HNO3 = 0.853 moles * 63.01 g/mol

Mass HNO3 = 53.7 grams

53.7 grams of HNO3 will be produced

3 0
3 years ago
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