The required spring constant:
The spring constant of the spring is .
Calculation:
The mass of the car is m=1200 kg, the speed of the car is v=25 m/s, and after colliding the spring is brought to rest at a distance of x=2.5m. Let the spring constant of the spring is, k.
From the conservation of energy,
Total initial kinetic energy= Total final potential energy of the spring
Therefore,
Now, substituting the values of the mass of the car, speed of the car, and displacement, we get:
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The answer is C, A, B in that order.
Pressure = Density * gravity * height.
Let us look at these three substances and assume gravity is 9.8 m/s squared.
The Salt water has a density of 1029kg/m3, height of 0.2 meters.
Pressure of salt water will be 1029*9.8*0,2 = 2,016 p
Fresh water has a density of 1000kg/m3
Pressure of salt water will be 1000*9.8*0.2 = 1,960 pa
Mercury has density of 13,534kg/m3
Pressure of mercury will be 13534*9.8*0.05 = 6,631 pa
So mercury exerts the highest pressure even at only 5cm height.
Answer:
So we need to add 13.46 gr of ice in order to reach the final equilibrium temperature of 49 C
Explanation:
For this case we need to use the fact that the sum for all the heats involved in the system are 0, since we assume an equilibrium state.
Data given
mass of the porcelain cup
the specific heat for the porcelain cup
initial temperature for the coffee and the porcelain cup.
Volume of the coffee.
We can convert this to m^3 and we got 0.000161m^3 and assuming the density fot the coffee equal to the water 1 Kg/m^3 the mass would be:
Specific heat for the coffee
mass of ice required
equilibrium temperature
represent the latent heat of fusin since the ice change the state to liquid.
Solution to the problem
Using this formula:
We have this:
Now we can replace and we have this:
And now we can solve for and we have:
So we need to add 13.46 gr of ice in order to reach the final equilibrium temperature of 49 C
Answer:
it should be -2m/s
Explanation:
Because it is going down from minutes 6-8. And down in most cases means negative. And since it is going down 2 it should be -2m/s.
Hope this helped!!
Answer:
Explanation:
As we know that the moment of area of polar is also known as the second moment of area. It is used to describe resistance to torsional deformation, on cylindrical objects with an invariant cross section area.
Therefore, mathematically second moment of area can be written as,
Here, R is the radius of circular cross section.
Given that a circular section is welded to a wall has a diameter,
Therefore,
Therefore, second moment of area for the circular weld pattern is,