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2 years ago

If an object is in freefall it will experience air blank which generates a drag force

Physics

2 answers:

kogti [31]2 years ago

5 0

Answer:

Resistance

Explanation:

I believe it is air resistance but I could be wrong.

tia_tia [17]2 years ago

4 0

The question is fishing for "air resistance", but that's a mistake by whoever wrote the question.

"Free fall" means that gravity is the ONLY force on the body. If there's any air resistance, then it's not free fall.

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What is the relationship between wavelength of light and the quantity of energy per photon?

slamgirl [31]

Answer:

The quantity of energy per photon is inversely proportional to the wavelength of the light.

Explanation:

Energy of light is given as

E = hf

where E = energy of the photons,

f = frequency of the light

If the number of photons = n

(E/n) = (h/n) f

Let (E/n) = E'

(h/n) = h'

But the frequency of light is related to wavelength through the relation

v = fλ

where v = speed of light = c

λ = wavelength of light

f = (c/λ)

E' = h' f

Substituting for f

E' = h' (c/λ)

h' and c are both constants, h'×c = K

E' = (K/λ)

So, the quantity of energy per photon is inversely proportional to the wavelength of the light.

Hope this Helps!!!

3 0

3 years ago

Read 2 more answers

A laser beam of wavelength λ=632.8 nm shines at normal incidence on the reflective side of a compact disc. The tracks of tiny pi

Juliette [100K]

To solve this problem we will apply the concepts given by the principles of superposition, specifically those described by Bragg's law in constructive interference.

Mathematically this relationship is given as

$dsin\theta = n\lambda$

Where,

d = Distance between slits

$\lambda$ = Wavelength

n = Any integer which represent the number of repetition of the spectrum

$\theta = sin^{-1} (\frac{n\lambda}{d})$

Calculating the value for n, we have

n = 1

$\theta_1 = sin^{-1} (\frac{\lambda}{d})\\\theta_1 = sin^{-1} (\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_1 = 23.3\°$

n=2

$\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (2\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = 52.28\°$

n =3

$\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (3\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = \text{not possible}$

Therefore the intensity of light be maximum for angles 23.3° and 52.28°

7 0

3 years ago

A battery is replaced with one of lower emf. State and explain how the resistance of the lamps would have to change in order to

kow [346]

The brightness of the lamp is proportional to the current flowing through the lamp: the larger the current, the brighter the lamp.

The current flowing through the lamp is given by Ohm's law:

$I=\frac{V}{R}$

where

V is the potential difference across the lamp, which is equal to the emf of the battery, and R is the resistance of the lamp.

The problem says that the battery is replaced with one with lower emf. Looking at the formula, this means that V decreases: if we want to keep the same brightness, we need to keep I constant, therefore we need to decrease R, the resistance of the lamp.

3 0

2 years ago

Which of the following best describes what causes the pases of the moon.?

Alborosie

The correct answer is<span> The earth casts a shadow on the moon

The Earth casts a shadow on the moon and that's why we can't see the remaining parts. The parts that we can see are what we call the lunar phases.</span>

4 0

2 years ago

A toy car starts from the rest and accelerates at 1.50m/s2 [E] for 2.25s. What is the final velocity, of the car

V125BC [204]

3.375m/s is the final velocity of the car.

<h3>How do you find final velocity?</h3>

The final velocity depends on how large the acceleration is and the distance over which it acts.

Initial velocity of an object, you can multiply the acceleration due to a force by the time the force is applied and add it to the initial velocity to get the final velocity.

According to the question,

A toy car starts from the rest and accelerates

So the acceleration = 1.50m/s²

Time = 2.25s

$x=x_{0} + vt$