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Radda [10]
3 years ago
12

If an object is in freefall it will experience air blank which generates a drag force

Physics
2 answers:
kogti [31]3 years ago
5 0

Answer:

Resistance

Explanation:

I believe it is air resistance but I could be wrong.

tia_tia [17]3 years ago
4 0

The question is fishing for "air resistance", but that's a mistake by whoever wrote the question.

"Free fall" means that gravity is the ONLY force on the body. If there's any air resistance, then it's not free fall.

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The speed of all electromagnetic waves is 3.00 × 108 meters per second. What is the wavelength of an X-ray with a frequency of 1
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The answer is......2.54x10^-10......
8 0
4 years ago
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A uniform solid disk and a uniform ring are place side by side at the top of a rough incline of height h.
nadezda [96]

Explanation:

velocity of disc =\sqrt((gh)/0.75)

lets call (h) 1 m to make it simple.

= 3.614 m/s

\sqrt((4/3) x 1 x 9.8) = 3.614 m/s pointing towards this:

4×V_d=\sqrt(4/3hg)

V_h=\sqrt(hg)

velocity of hoop=\sqrt(gh)

lets call (h) 1m to make it simple again.

\sqrt(9.8 x 1) = 3.13 m/s

\sqrt(gh) = sqrt(hg)so [tex]4×V_d= \sqrt(4/3hg)V_h=\sqrt(hg)

The disc is the fastest.

While i'm on this subject i'll show you this:

Solid ball =0.7v^2= gh

solid disc = 0.75v^2 = gh

hoop =v^2=gh

The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.

The solid ball will be the faster of the 3, like above i'll show you.

solid ball: velocity =\sqrt((gh)/0.7)

let (h) be 1m again to compare.

\sqrt((9.8 x 1)/0.7) = 3.741 m/s

solid disk speed =\sqrt((gh)/0.75)

uniform hoop speed =\sqrt(gh)

solid sphere speed =\sqrt((gh)/0.7)

8 0
3 years ago
Attractions between oppositely charged regions of nearby molecules are called
Reptile [31]

Answer:van der Waals forces

Explanation:van der Waals forces are weak bond that occurs between oppositely charged molecules like in the case of a magnet

5 0
3 years ago
100 POINTS!!!
nignag [31]

Answer:

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6 0
3 years ago
PLZ HELP ME
bonufazy [111]

Answer:

1. The stone will strike the ground 49.46 m from the base of the cliff

2. A) Approximately 0.542 seconds

B)  Approximately 3.69 m/s

3. A) The time the ball spends in the air is approximately 4.0775 s

B) The horizontal range is approximately  141.25 m.

Explanation:

1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)

∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds

The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m

The stone will strike the ground 49.46 m from the base of the cliff

2. A) The time the ball spends in the air = t = √(h/(1/2 × g)

∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds

B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s

The initial horizontal velocity ≈ 3.69 m/s

3. A) The time the ball spends in the air is given by the following equation;

t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s

t ≈ 4.0775 s

B) The horizontal range, R, of the  ball is given by the equation for the range of a projectile as follows;

Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}

Substituting the known values, gives;

Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m

The horizontal range ≈ 141.25 m.

4 0
3 years ago
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