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2 years ago

Which represents the order of the forces from weakest to strongest.

1 answer:

5 0

Force is studied by physics and according to it four fundamental forces are recognized at the quantum level ordered from weakest to strongest are: the gravitational force, the weak nuclear force, the electromagnetic force and the strong nuclear force.

<h3>What is force?</h3>

It is that magnitude that affects a body and is responsible for changes in its state of motion, according to quantum mechanics ordered from weakest to strongest are:

Gravitational force is the force exerted by one mass on the other, being a weak force.

Weak nuclear force is the force responsible for radioactive decay.

Electromagnetic force is the force that affects electrically charged particles and has two directions (attraction-repulsion).

Strong nuclear force is the force that keeps the nuclei of atoms stable, being stronger than the electromagnetic force.

Therefore, we can conclude that four fundamental forces are recognized at the quantum level ordered from weakest to strongest are: the gravitational force, the weak nuclear force, the electromagnetic force and the strong nuclear force.

Learn more about fundamental forces here: brainly.com/question/910002

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a 5 kg block is pulled across a table by a horizontal force of 40 n with a frictional force 8 n opposing the motion. calculate t

MAXImum [283]

By Newton's 2nd law, m*a=sum_of_forces where m is the mass and a the acceleration. Here there are two forces in opposed directions.

Thus 5*a=40-8=32 therefore a=32/5=6.4m^s/2

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4 years ago

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Is a reflection matter?

azamat

Answer:

Yes, because everything bounce off in every surface around any object.

Explanation:

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4 years ago

What is the frequency of a sound wave traveling at 335 m/s with a wavelength of .55 m?

irga5000 [103]

Answer:

v=f* lamba

f=v/lamba

f= 335/55

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3 years ago

A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q

Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges $q_1$ and $q_2$ separated by a distance d, the magnitude of the electrostatic force F between them is:

$F = k \frac{|q_1q_2|}{d^2}$

where $k$ is Coulomb's constant.

Taking the values:

$d = 4.6 \ 10^{-15} m$

$q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}$

and knowing the value of the Coulomb's constant:

$k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}$

Taking all this in consideration:

$F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}$

$F = 120.85 \ N$

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3 years ago

i need help please. this is for physics but everything i search for related to this comes up as chemistry

Annette [7]

The car tyre contains air initially at a pressure of 195 kPa after travelling several km the temperature of the air inside a car tyre rises from 30 to 70°C if the tyre is rigid and does not expand then the new pressure inside the tyre would be 220.74 kPa.

<h3>What is pressure?</h3>

The total applied force per unit of area is known as the pressure.

The pressure depends both on externally applied force as well the area on which it is applied.

The mathematical expression for the pressure

Pressure = Force /Area

the pressure is expressed by the unit pascal or N /m²

By using the Charles law for gases which states that the volume of the gas remains constant then the pressure of the gas is directly proportional to the temperature.

As given in the problem the tyre is rigid and does not expand this means the volume of the tyre remains constant.

The mathematical expression for Charles's law is as follows

P₁/P₂ = T₁/T₂

First, we have to change the temperature from degree Celcius to the kelvin temperature scale

K = 273 + C

where k is the temperature in kelvin and the C is degrees of Celcius

Initially, the temperature was 30° C

T₁ = 273 + 30

T₁ = 303 K

Then after travelling the temperature of the air inside a car tyre rises from 30 to 70°C

T₂= 273+ 70

T₂ =343 K

The car tyre contains air initially at a pressure of 195 KPa

P₁ = 195 kPa

Lets us take the final pressure of the air would be P₂

By substituting the values in the formula

P₁/P₂ = T₁/T₂

195/P₂ = 303/343

P₂ = 220.74 kPa

Thus, the new pressure inside the tyre would be 220.74 kPa.

Learn more about pressure learn more

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2 years ago