Answer:
b) the second at the doorknob.
Explanation:
The torque applied by a force is given by the equation
where
is the torque
is the component of the force perpendicular to the direction between the axis of rotation and the point of application of the force
d is the arm (the distance between the axis of rotation and the point of application of the force)
In this problem, we have two equal forces F both applied perpendicular to a door, so
The first force is applied at the midpoint of the door; if we call L the width of the door, then the arm of this force is 
, so the torque applied by this first force is
The 2nd force instead is applied at the doorknob, so the arm in this case is L:
d = L
So, the torque exerted by the second force is
Therefore, we see that the 2nd force exerts a greater torque.
Answer:
a) 0.0130 m
b') w' = =6.46*10^{-3] m
Explanation:
given data:
\lambda of light = 633 nm
width of siit a =0.360 mm
distance from screen = 3.75 m
a) the first minima is located at
=
with of central fringe = 2y_1 = 2*6.54 *10^{-3} = 0.0130 m
b)
width of the first bright fringe on either side of the central one = 
calculation for y_2
= 
w' = =6.46*10^{-3] m
Answer:
hello your question lacks the required diagram attached below is the complete question with the required diagram
answer : Qtotal = 807.4 Mw
Explanation:
Given Data :
disk properties :
∈ = 0.65
D = 200 mm
Ts = 400⁰c
attached below is the detailed solution
The total rate of Heat transferred from the disk
Qtotal = 807.4 Mw
Answer:
Explanation:
We put the charges in the ascending order as follows
1.53 P
3.26 P
4.66 P
5.09 P
6.39 P
where P is equal to 10⁻¹⁹
we round off given charges as follows
1.53 P → 1.6 P
3.26 P → 3.2 P
4.66 P → 4.8 P
5.09 P → 4.8 P
6.39 P → 6.4 P
We see that 2 nd to 4 th charges are integral multiples of first charge . That means these charges are supposed to be made of combination of first charge . So first charge appears to be minimum possible charge .
Hence this charge may exist on single electron.
Explanation:
voltage = current × resistance
5.
12 V = 4.2 A × resistance
resistance = 12 V / 4.2 A = 2.857142857... Ohm
FYI :
4.2 A would be a lot for a small electronic device like a CD player. that would be 12×4.2 = 50.4 Watt, and the CD player would get really hot.
6.
120 V = current × 12 Ohm
current = 120 V / 12 Ohm = 10 A
