You are comparing a reaction that produces a chemical change and one that produces a physical change. What evidence could you us
2 answers:
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Answer:
A. speed = 7.14 Km/s
B. distance = 1820.7 Km
Explanation:
Given that: a = 14.0 m/, t = 8.50 minutes.
But,
t = 8.50 = 8.50 x 60
= 510 seconds
A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;
v = u + at
where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
u = 0
So that,
v = 14 x 510
= 7140 m/s
The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.
B. the distance traveled can be determined by applying second equation of motion.
s = ut + a
where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.
u = 0
s = a
= x 14 x
= 7 x 260100
= 1820700 m
The distance that the shuttle has traveled during the given time is 1820.7 Km.
Answer:
Eo = 9.796 x 10^2 N/C
Bo = 3.266 x 10^-6 T
Explanation:
Given
Wavelength λ = 633 nm
Diameter of the beam D = 1.0 mm
Power P = 1.0 mW
Solution
Radius of the beam r = D/2 = 0.5 mm = 0.0005 m
Area of cross section
Intensity
Amplitude of Electric Field
Amplitude of Magnetic Field