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4 years ago

Write a linear function ff with f(−2)=6f(−2)=6 and f(0)=−4f(0)=−4

1 answer:

3 0

You are given two points (-2, 6) and (0, -4)
find the slope: m=(-4-6)/[(0-(-2)]=-5
So you have y=-5x+b
next, find the y intercept b.
the y intercept is when x=0. in this case, the y intercept is -4
so y=-5x-4

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Which of the following represents a geometric series (remember what a series is as opposed to a sequence)?

juin [17]

Answer:

4 + 12 + 36 + ...

Step-by-step explanation:

4, 12, 36, ... is a geometric sequence, it has a common ratio of $r=\frac{36}{12}=\frac{12}{4}=3$

When we add the terms of a geometric sequence we get a geometric series.

4+12+36+ ... is a geometric series, it has a common ratio of $r=\frac{36}{12}=\frac{12}{4}=3$

4 + 12 + 20 + ... is not a geometric series because it has no common ratio

$\frac{20}{12}\ne \frac{12}{4}$

The second choice is correct

8 0

3 years ago

Answer my questions and i will mark you as brainliest i promise trust me

Kazeer [188]

Answer:

1.042g/cm^3

Step-by-step explanation:

4 0

4 years ago

A park is mapped on a coordinate plane, where C1, C2, C3, and C4 represent chairs and SW1, SW2, and SW3 represent swings. How fa

serg [7]

Answer:

Option (B)

Step-by-step explanation:

To calculate the distance between C2 and SW1 we will use the formula of distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ .

d = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }$

Coordinates representing positions of C2 and SW1 are (2, 2) and (-6, -7) respectively.

By substituting these coordinates in the formula,

Distance between these points = $\sqrt{(-6-2)^2+(-7-2)^2}$

= $\sqrt{(64)+(81)}$

= $\sqrt{145}$ units

Therefore, Option (B) will be the correct option.

5 0

4 years ago

Read 2 more answers

The rectangle has an area of x square plus 15 square meters and a width of X plus 3

hammer [34]

Answer:

x + 5

Step-by-step explanation:

4 0

3 years ago

Answer if you know

Arlecino [84]

I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set $y=1.25$ for this example.)

The length of each cross section (the side lying in the base) has length determined by the horizontal distance $x$ between the y-axis $x=0$ and the curve $y=\sqrt x$ . In terms of $y$ , this distance is $x=y^2$ . The height of each cross section is twice the value of $y$ , so the area of each rectangular cross section should be $2y^3$ .

This means the volume would be given by the integral

$\displaystyle\int_0^22y^3\,\mathrm dy$

8 0

3 years ago