Question

Immunoglobulin G (IgG), formerly called gamma globulin, is a principal antibody in blood serum. A 0.470 g sample of immunoglobulin G is dissolved in water to make 0.106 L of solution, and the osmotic pressure of the solution at 25 ∘C is found to be 0.733 mbar. Calculate the molecular mass of immunoglobulin G.

Answer 1

The molecular mass of the immunoglobulin G, given the data from the question is 1.53×10⁵ g/mole

How to determine the molarity

We'll begin by calculating the molarity of the immunoglobulin G. This is illustrated below:

• Volume = 0.106 L
• Temperature (T) = 25 °C = 25 + 273 = 298 K
• Osmotic pressure (π) = 0.733 mbar = 0.733 × 0.000987 = 0.00072 atm
• Gas constant (R) = 0.0821 atm.L/Kmol
• Van't Hoff factor (i) = 1
• Molarity (M)

π = iMRT

M = π / iRT

M = 0.00072 / (1 × 0.0821 × 298)

M = 0.000029 M

How to determine the mole of immunoglobulin G

• Molarity = 0.000029 M
• Volume = 0.106 L
• Mole =?

Mole = Molarity × volume

Mole = 0.000029 × 0.106

Mole = 3.074×10⁻⁶ mole

How to determine the molar mass of mmunoglobulin G

• Mole = 3.074×10⁻⁶ mole
• Mass = 0.470 g
• Molar mass =?

Molar mass = mass / mole

Molar mass = 0.47 / 3.074×10⁻⁶

Molar mass = 1.53×10⁵ g/mole

Learn more about Osmotic pressure:

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